I think i see what he means the answer is B.
but correct me if i'm wrong.
Answer:
<u>Part A</u> : 70 secondary oocytes will be formed.
<u>Part B</u> : 70 first polar bodies will be formed.
<u>Part C</u> : 70 ootids will be formed.
Explanation:
During oogenesis growth maturation of a single oogonium produces one primary oogonium.
the primary oogonium then undergoes meiosis -1 and produces one secondary oocyte and first polar body.
The secondary oocyte then undergoes meiosis - 2 and forms an ootid and second polar body.
The ootid then differentiates into the ovum.
As in the above scenario , 70 primary oocytes are present , they undergo meiosis-1 and produces 70 secondary oocytes and 70 first polar bodies. Hence answers of part A and B is 70.
As 70 secondary oocytes are formed , they undergo meiosis -2 and forms 70 ootids which then differentiate in 70 ovums.
Correct answer: A). The enzyme influences the speed of change from substrate to product
The enzymes are the biological catalyst that speed up the rate of chemical reactions by decreasing the activation energy of the reaction pathway.
They increase the speed of change of substrate to the product and it remains unchanged in the reaction. Hence, it can be used again and again.
Enzymes are highly specific in nature, only a specific substrate binds to the enzyme's active site. Hence, a particular enzyme is required to catalyze a reaction.
