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marta [7]
2 years ago
11

At a local clothing store, Morgan finds they are having a storewide 40% off sale. She also has a $15 coupon which applies to her

total purchase. When the sales clerk processes Morgan's order, she first applies the $15 off coupon, then takes the 40% off the remaining balance. Which order of the discounts is best for Morgan.
Mathematics
1 answer:
LuckyWell [14K]2 years ago
5 0

Morgan should first take the 40% off then apply the $15 coupon

Lets say her total was $150.

If you take the 40% off first, you get $90

150 * .6 = 90 (since you are taking off 40% you are still paying the rest of the 60% so you can just save extra steps by multiplying by .6 and not .4)

Now you subtract 15 from that value.

90 - 15 = 75 If Morgan takes the 40% off first and then applies the $15 dollar coupon, she has to pay $75.

If she applies the $15 coupon first, her total before the 40% is $135

150 - 15 = 135

The total will come out to be $81

$135 * .6 = 81

If Morgan takes the discount first before applying the coupon she has to pay less and saves the most money.

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Matthew is 7 years older than twice the age of his sister. If Matthew is 13, how old is his sister?
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Let sister be s.  Matthew, M

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Can someone please give me the answers
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Answer:

1) 3

2)9

3)18

4)18k

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2 years ago
The reference desk of a university library receives requests for assistance. Assume that a Poisson probability distribution with
NISA [10]

Answer:

a) 0.125

b) 7

c) 0.875 hr

d) 1 hr

e) 0.875

Step-by-step explanation:l

Given:

Arrival rate, λ = 7

Service rate, μ = 8

a) probability that no requests for assistance are in the system (system is idle).

Let's first find p.

a) ρ = λ/μ

\frac{7}{8} = 0.875

Probability that the system is idle =

1 - p

= 1 - 0.875

=0.125

probability that no requests for assistance are in the system is 0.125

b) average number of requests that will be waiting for service will be given as:

λ/(μ - λ)

= \frac{7}{8 - 7}

= 7

(c) Average time in minutes before service

= λ/[μ(μ - λ)]

= \frac{7}{8(8 - 7)}

= 0.875 hour

(d) average time at the reference desk in minutes.

Average time in the system js given as: 1/(μ - λ)

= \frac{1}{(8 - 7)}

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(e) Probability that a new arrival has to wait for service will be:

λ/μ =

{7}{8}

= 0.875

5 0
3 years ago
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