The function F(x) have a vertical asymptote at x =0 and x =1.
Given that
The given Function;
We have to determine
At which value the function F(x) has a vertical asymptote.
According to the question
The given Function;
The function is undefined when the denominator becomes 0. Find values of x for which the denominator is 0:
Then,
The value of x is 0 and 1.
Hence, the function F(x) have a vertical asymptote at x =0 and x =1.
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Answer:
If we used the quadratic formula to solve the equation we can say:
-b = -5
b² - 4ac = 13
2a = 2
Solving the first and last equations we get b = 5 and a = 1. Substituting these values into the second equation we get:
25 - 4c = 13
Solving this we get c = 3 so the answer is x² + 5x + 3.
The answer is C 2/5 = 0.4
Answer:
A
Step-by-step explanation:
given 2 secants drawn from an external point to the circle , then
the product of the measures of one secant's external part and that entire secant is equal to the product of the other secant's external part and that entire secant, that is
9(9 + 2 + 3x) = 10(10 + 2x + 2)
9(11 + 3x) = 10(12 + 2x) ← distribute parenthesis on both sides
99 + 27x = 120 + 20x ( subtract 20x from both sides )
99 + 7x = 120 ( subtract 99 from both sides )
7x = 21 ( divide both sides by 7 )
x = 3
Answer:
idk how to do this
Step-by-step explanation:
Sorry tho
