Answer: look at the picture
Step-by-step explanation: Hope this help :D
Answer:
You invested $22,000 in two accounts paying 3% and 5% annual interest, respectively. If the total interest earned for the year was $980, how much was invested at each rate?
Step-by-step explanation:
let x=amt invested at 3% rate of interest.
22000-x=amt invested at 5% rate of interest.
.03x+.05(22000-x)=980
.03x+1100-.05x=980
.02x=120
x=6000
22000-x=16000
amt invested at 3% rate of interest=$6,000
amt invested at 5% rate of interest=$16,000
<h2><em><u>Hope iit help you mark as Brainlist</u></em></h2>
(x - 1)(x - 2)(x + 2)
note that the sum of the coefficients 1 - 1 - 4 + 4 = 0
thus x = 1 is a root and (x - 1 ) is a factor
dividing x³ - x² - 4x + 4 by (x - 1)
x³ - x² - 4x + 4 = (x - 1)(x² - 4 ) (note (x² - 4 ) is a difference of squares )
x³ - x² - 4x + 4 = (x - 1)(x - 2)(x + 2)
(x - 1)(x - 2)(x + 2 ) =0
x - 1 = 0 ⇒ x = 1
x - 2 = 0 ⇒ x = 2
x + 2 = 0 ⇒ x = - 2
solutions are x = 1 or x = ± 2
The answer for this proportion is 50.
156.25 times 16 =2,500
2,500 divided by 50=50
X=50
Answer:
Answer a h bro ok bye bro good luck
