The interval estimate of a population parameter is an interval of values that consist of the values within which the true value of the parameter lies with a certain probability.

The mean of the sampling distribution of sample proportion is, $\hat p$ .

One of the best interval estimate of population proportion is the 95% confidence interval for proportion,

$CI=\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}$

Given:

n = 150

$\hat p$ = 0.68

The critical value of <em>z</em> for 95% confidence level is:

$z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96$

Compute the 95% confidence interval for proportion as follows:

$CI=\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}$

$=0.68\pm1.96\sqrt{\frac{0.68(1-0.68)}{150}}\\\\=0.68\pm 0.0747\\\\=(0.6053, 0.7547)\\\\\approx (0.61, 0.75)$

Thus, the reasonable range for the population mean is (61%, 75%).

5 0

3 years ago

Convert the decimal expansion 0.31717 to a fraction.

Ipatiy [6.2K]

0.31717 can be written as the fraction <span>31717/100000.

I hope this help :P</span>

4 0

3 years ago

Greg has 5 coins in his pocket. The value of all 5 coins is $0.57m which coins does he have in jis pocket

Step2247 [10]

Test all answer choices:
A) 0.25+0.20+0.02 = 0.47 - incorrect
B) 0.75+0.02 = 0.77 - incorrect
C) 0.50+0.05+0.02 = 0.57 correct
D) 0.50+0.10+0.02 = 0.62 incorrect

The correct answer is C.

4 0

3 years ago

Read 2 more answers