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liberstina [14]
3 years ago
7

Select the correct answer. Thank you

Mathematics
1 answer:
Setler79 [48]3 years ago
7 0

Answer:

I think a

Step-by-step explanation:

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A steel cargo container is shaped like a cube measuring 5.2 ft on each edge how much steel is needed to make this container? Sho
bearhunter [10]

Answer:

162.24 ft

Step-by-step explanation:

So you first find the area of one side.

5.2 x 5.2 = 27.4

Then you times it by 6, because a cube has 6 sides.

27.4 x 6 = 162.24 ft

6 0
3 years ago
Answer quick for brainliest
scoray [572]

Answer:

y = 4x + 5

Step-by-step explanation:

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What is the answer to this? Will give brainiest 5[(6-3)^(2)+4*2]=
mylen [45]
85 is the correct answer.
8 0
2 years ago
Which of the following is an improper integral?
guapka [62]

Answer:

A)  \displaystyle \int\limits^3_0 {\frac{x + 1}{3x - 2}} \, dx

General Formulas and Concepts:

<u>Calculus</u>

Discontinuities

  • Removable (Hole)
  • Jump
  • Infinite (Asymptote)

Integration

  • Integrals
  • Definite Integrals
  • Integration Constant C
  • Improper Integrals

Step-by-step explanation:

Let's define our answer choices:

A)  \displaystyle \int\limits^3_0 {\frac{x + 1}{3x - 2}} \, dx

B)  \displaystyle \int\limits^3_1 {\frac{x + 1}{3x - 2}} \, dx

C)  \displaystyle \int\limits^0_{-1} {\frac{x + 1}{3x - 2}} \, dx

D) None of these

We can see that we would have a infinite discontinuity if x = 2/3, as it would make the denominator 0 and we cannot divide by 0. Therefore, any interval that includes the value 2/3 would have to be rewritten and evaluated as an improper integral.

Of all the answer choices, we can see that A's bounds of integration (interval) includes x = 2/3.

∴ our answer is A.

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit:  Integration

Book: College Calculus 10e

6 0
3 years ago
Find the slope(-1,-1),(2,-2)
Natali [406]

Answer:

\huge\boxed{slope=-\dfrac{1}{3}}

Step-by-step explanation:

The formula of a slope:

m=\dfrac{y_2-y_1}{x_2-x_1}

Substitute the coordinates of the given points (-1, -1) and (2, -2):

m=\dfrac{-2-(-1)}{2-(-1)}=\dfrac{-2+1}{2+1}=\dfrac{-1}{3}=-\dfrac{1}{3}

5 0
3 years ago
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