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3 years ago

Select the correct answer. Thank you

Mathematics

1 answer:

Setler79 [48]3 years ago

7 0

Answer:

I think a

Step-by-step explanation:

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Answer choices - a: x = -9 b: x = 2 c: x = -4/3 d: x = 67

s2008m [1.1K]

Where is the problem or question?

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2 years ago

Zadanie optymalizacyjne z matematyki. Proszę o rozwiązanie i wyjaśnienie

Yakvenalex [24]

Volume of the pyramid:

$V=\dfrac{s^2h}3$

Perimeter of the cross-section:

$40=\sqrt2\,s+2\sqrt{\dfrac{s^2}2+h^2}=\sqrt2\left(s+\sqrt{s^2+2h^2}\right)$

$\implies h=\sqrt{\dfrac{(20\sqrt2-s)^2-s^2}2}=\sqrt{400-20\sqrt2\,s}$

Area of the cross-section:

$P=\dfrac12(\sqrt2\,s)h=\dfrac{sh}{\sqrt2}$

$\implies P=\dfrac{s\sqrt{400-20\sqrt2\,s}}{\sqrt2}=s\sqrt{200-10\sqrt2\,s}$

First derivative test:

$\dfrac{\mathrm dP}{\mathrm ds}=\dfrac{20\sqrt2-3s}{\sqrt{4-\dfrac{\sqrt2}5s}}=0\implies s=\dfrac{20\sqrt2}3$

Then the height of the cross-section/pyramid is

$h=\sqrt{400-20\sqrt2\,s}=\dfrac{20}{\sqrt3}$

The volume of the pyramid that maximizes the cross-sectional area $P$ is

$V=\dfrac{\left(\frac{20\sqrt2}3\right)^2\frac{20}{\sqrt3}}3=\dfrac{16000}{27\sqrt3}$

5 0

3 years ago

Help please i really need this done

Inga [223]

Answer:

x = 33°

Step-by-step explanation:

x = 180° - 80° - 67° = 33°

5 0

2 years ago

Read 2 more answers

Delta Airlines quotes a flight time of 2 hours for its flights from Cincinnati to Tampa, meaning that an on-time flight would ar

ddd [48]

Answer:

a) Attached

b) P=0.60

c) P=0.80

d) The expected flight time is E(t)=122.5

Step-by-step explanation:

The distribution is uniform between 1 hour and 50 minutes (110 min) and 135 min.

The height of the probability function will be:

$h=\frac{1}{Max-Min}=\frac{1}{135-110} =\frac{1}{25}$

Then the probability distribution can be defined as:

$f(t)=\frac{1}{25}=0.04 \,\,\,\,\\\\t\in[110,135]$

b) No more than 5 minutes late means the flight time is 125 or less.

The probability of having a flight time of 125 or less is P=0.60:

$F(T$

c) More than 10 minutes late means 130 minutes or more

The probability of having a flight time of 130 or more is P=0.80:

$F(T>t)=1-0.04(t-110)\\\\F(T>130)=1-0.04*(130-110)=1-0.04*20=1-0.8=0.2$

d) The expected flight time is E(t)=122.5

$E(t)=\frac{1}{2}(max+min)= \frac{1}{2}(135+110)=\frac{1}{2}*245=122.5$

6 0

2 years ago

Determine the standard deviation (sigma)by filling in the table as part of your calculation. Consider the following data 6, 6, 1

12345 [234]

Answer:

Step-by-step explanation:

I got it right on the assignment 100%

6 0

2 years ago

Read 2 more answers