Where is the problem or question?
Volume of the pyramid:

Perimeter of the cross-section:


Area of the cross-section:


First derivative test:

Then the height of the cross-section/pyramid is

The volume of the pyramid that maximizes the cross-sectional area
is

Answer:
x = 33°
Step-by-step explanation:
x = 180° - 80° - 67° = 33°
Answer:
a) Attached
b) P=0.60
c) P=0.80
d) The expected flight time is E(t)=122.5
Step-by-step explanation:
The distribution is uniform between 1 hour and 50 minutes (110 min) and 135 min.
The height of the probability function will be:

Then the probability distribution can be defined as:
![f(t)=\frac{1}{25}=0.04 \,\,\,\,\\\\t\in[110,135]](https://tex.z-dn.net/?f=f%28t%29%3D%5Cfrac%7B1%7D%7B25%7D%3D0.04%20%5C%2C%5C%2C%5C%2C%5C%2C%5C%5C%5C%5Ct%5Cin%5B110%2C135%5D)
b) No more than 5 minutes late means the flight time is 125 or less.
The probability of having a flight time of 125 or less is P=0.60:

c) More than 10 minutes late means 130 minutes or more
The probability of having a flight time of 130 or more is P=0.80:

d) The expected flight time is E(t)=122.5

Answer:
A
Step-by-step explanation:
I got it right on the assignment 100%