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Annette [7]
3 years ago
11

Jk=8x+6 and kL=6x+20 Find JL

Mathematics
1 answer:
mr Goodwill [35]3 years ago
3 0
Jk=8x+6
J=(8x+6)/k

kL=6x+20
L=(6x+20)/k

JL=(8x+6)/k * (6x+20)/k
=(48x²+196x+120)/k²
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In parallelogram EFGH, the measure of angle G is (4x + 16)° and the measure of angle H is (2x − 16)°. What is the measure of ang
asambeis [7]

Answer:

m∠H = 44°

Step-by-step explanation:

Consecutive angles of a parallelogram are supplementary.  So,

∠H and ∠G are supplementary

4x + 16 + 2x - 16 = 180

6x = 180

x = 30

m∠H = 2x - 16 = 2(30) - 16 = 60 - 16 = 44°

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2 years ago
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Step-by-step explanation:

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The 2008 Workplace Productivity Survey, commissioned by LexisNexis and prepared by World One Research, included the question, "H
LenaWriter [7]

Answer:

A 95% confidence interval estimate of the mean number of hours a legal professional works on a typical workday is [7.44 hours, 10.56 hours].

Step-by-step explanation:

We are given that x is normally distributed with a known standard deviation of 12.6.

A sample of 250 legal professionals was surveyed, and the sample's mean response was 9 hours.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

                               P.Q.  =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample average mean response = 9 hours

            \sigma  = population standard deviation = 12.6

            n = sample of legal professionals = 250

            \mu = mean number of hours a legal professional works

<em>Here for constructing a 95% confidence interval we have used One-sample z-test statistics as we know about population standard deviation.</em>

<u>So, 95% confidence interval for the population mean, </u>\mu<u> is ;</u>

P(-1.96 < N(0,1) < 1.96) = 0.95  {As the critical value of z at 2.5% level

                                                   of significance are -1.96 & 1.96}  

P(-1.96 < \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } < 1.96) = 0.95

P( -1.96 \times {\frac{\sigma}{\sqrt{n} } } < {\bar X-\mu} < -1.96 \times {\frac{\sigma}{\sqrt{n} } } ) = 0.95

P( \bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } } < \mu < \bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } } ) = 0.95

<u>95% confidence interval for</u> \mu = [ \bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } } , \bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } } ]

                                       = [ 9-1.96 \times {\frac{12.6}{\sqrt{250} } } , 9+1.96 \times {\frac{12.6}{\sqrt{250} } } ]

                                       = [7.44 hours, 10.56 hours]

Therefore, a 95% confidence interval estimate of the mean number of hours a legal professional works on a typical workday is [7.44 hours, 10.56 hours].

5 0
2 years ago
1. write an equvialent expression: -1/2 (-2x + 4y)
Ierofanga [76]

Answer:

Step-by-step explanation:

I've answered this question already.

5 0
2 years ago
Divide (x^2-3x-5)/(x-4)​
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Answer:

[89]<100/:

Step-by-step explanation:

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3 years ago
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