Answer:
<em></em>![\left[\begin{array}{ccc}2&-6&2\\0&3&-2\\0&2&2\end{array}\right] \left[\begin{array}{ccc}x\\y\\z\end{array}\right]= \left[\begin{array}{ccc}1\\-5\\-3\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%26-6%262%5C%5C0%263%26-2%5C%5C0%262%262%5Cend%7Barray%7D%5Cright%5D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dx%5C%5Cy%5C%5Cz%5Cend%7Barray%7D%5Cright%5D%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%5C%5C-5%5C%5C-3%5Cend%7Barray%7D%5Cright%5D)
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Step-by-step explanation:
Given system of equations are
2x-6y-2z = 1
3y - 2z = -5
2y + 2z = -3
given
2 x - 6 y - 2 z = 1
0 x + 3 y - 2z = -5
0 x +2y + 2 z = - 3
<em>The Matrix form of the given system of equations </em>
<em>A X = B</em>
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Answer:
One pound equals $38.4
Step-by-step explanation:
Times the ounces by the cost
Answer:
B
Step-by-step explanation:
3% = 3/100
So we can eliminate the first answer.
The proportions have to match each other so the number nine should be above and thus the x has only the option of being under it.
As a result, we eliminate the third answer and remain with one reasonable answer
Given:
The parallel sides of a trapezium are 28.7 cm and 22.3 cm.
The distance between parallel sides is 16 cm.
To find:
The area of a trapezium.
Solution:
The area of the trapezium is:
Where, 
are parallel sides and 
is the vertical distance between the parallel sides.
Putting 
in the above formula, we get
Therefore, the area of the trapezium is 408 square cm.
Answer:
The fourth one
Step-by-step explanation:
I know that is correct
