All categories

3 years ago

The cost of a game that was p dollars with a 15% off coupon online plus $1.99 for shipping

Mathematics

1 answer:

Shtirlitz [24]3 years ago

8 0

(p - 0.15p) + 1.99

This is the equation to solve.

p minus 15% of p, plus 1.99 for shipping costs.

You might be interested in

3,619 people can fit in the auditorium for the concert. Twenty buses arrive with 68 people on each bus going into the auditorium

Sonja [21]

So 20x68 is 1360 so 3,619 -1,360 is 2,259 so 2,259 more people will be able to fit inside of the auditorium-hope this helped you

5 0

3 years ago

Pregnant women metabolize some drugs at a slower rate than the rest of the population. The half-life of caffeine is about 4 hour

UkoKoshka [18]

Answer:

Husband:

The husband will have 16.35 mg of caffeine in his body at 7 pm.

Woman:

The pregnant woman will have 51.33 mg of caffeine in her body at 7 pm.

Step-by-step explanation:

The amount of caffeine in the body can be modeled by the following equation:

$C(t) = C(0)e^{rt}$

In which C(t) is the amount of caffeine t hours after 8 am, C(0) is how much coffee they took and r is the rate the the amount of caffeine decreases in their bodies.

110 mg of caffeine at 8 am,

So $C(0) = 110$

Husband

Half life of 4 hours. So

$C(4) = 0.5C(0) = 0.5*110 = 55$

$C(t) = C(0)e^{rt}$

$55 = 110e^{4r}$

$e^{4r} = 0.5$

Applying ln to both sides

$\ln{e^{4r}} = \ln{0.5}$

$4r = \ln{0.5}$

$r = \frac{\ln{0.5}}{4}$

$r = -0.1733$

So for the husband

$C(t) = 110e^{-0.1733t}$

At 7 pm

7 pm is 11 hours after 8 am, so this is C(11)

$C(t) = 110e^{-0.1733t}$

$C(11) = 110e^{-0.1733*11} = 16.35$

The husband will have 16.35 mg of caffeine in his body at 7 pm.

Pregnant woman

Half life of 10 hours. So

$C(10) = 0.5C(0) = 0.5*110 = 55$

$C(t) = C(0)e^{rt}$

$55 = 110e^{10}$

$e^{10r} = 0.5$

Applying ln to both sides

$\ln{e^{10r}} = \ln{0.5}$

$10r = \ln{0.5}$

$r = \frac{\ln{0.5}}{10}$

$r = -0.0693$

At 7 pm

7 pm is 11 hours after 8 am, so this is C(11)

$C(t) = 110e^{-0.0693t}$

$C(11) = 110e^{-0.0693*11} = 51.33$

The pregnant woman will have 51.33 mg of caffeine in her body at 7 pm.

7 0

3 years ago

Name the maximum and minimum of the function

stiv31 [10]

The alimentary canal and the gastrointestinal tract (GI tract)

8 0

3 years ago

At a carnival, the cost to play a bowling game is $2, plus $0.40 for each attempt to knock over the pins. Which inequality would

liq [111]

Answer:

Step-by-step explanation:

7 0

3 years ago

Help me please it’s due today

pentagon [3]

Answer:

1. B. $20

2.C. 19%

3. D. not here

Step-by-step explanation:

1. info we know

25+45+10+25+15+10 = 130

we need 20 more dollars

2. 25/130 x/100

cross multiply

2500/ 130x

divide

19 = x

3. same steps as last time

35/130 x/100

3500/130x

29%

5 0

3 years ago