Answer:
= 99 Ω
= 2.3094 Ω
P(98<R<102) = 0.5696
Step-by-step explanation:
The mean resistance is the average of edge values of interval.
Hence,
The mean resistance,
= 99 Ω
To find the standard deviation of resistance, we need to find variance first.

Hence,
The standard deviation of resistance,
= 2.3094 Ω
To calculate the probability that resistance is between 98 Ω and 102 Ω, we need to find Normal Distributions.


From the Z-table, P(98<R<102) = 0.9032 - 0.3336 = 0.5696
Answer:
$22.5
Step-by-step explanation:
2.5% = .025
900 divided by 1.5 = 600
600 multiplied by .025 = 15
15 divided by .5 = 7.5
15 + 7.5 = 22.5
Answer:108
Step-by-step explanation:
57.5 is the answer. Because think of 200 as 100% and 15 out of a hundered is ______. Right.