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3 years ago

Please help me out please

Mathematics

1 answer:

Oxana [17]3 years ago

7 0

In any trapezoid, the area is given by

$A = \dfrac{(B+b)h}{2}$

where B and b are the two bases, and h is the height. You're given all these elements already, so you only need to plug the values in:

$A = \dfrac{(3+11)\cdot 8}{2} = \dfrac{14\cdot 8}{2} = 7\cdot 8 = 56$

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What is the width of a rectangle with length 14 cm and area 161 cm to the 2nd power?

WINSTONCH [101]

A=l*w
161=14w

161/14=w

11.5cm is the width

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3 years ago

if $55 is put in an account that gets 6% and i add $20 at the end of each year, how much will i have at the end of 10 years?

dolphi86 [110]

I will not give you the answer but I will show you how to solve this.

55*.6= A
65*.6=B
75*.6=C
85*.6 = D

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3 years ago

Convert 0∘F to ∘C. Round to one decimal place.

Gennadij [26K]

Answer:

(0°F − 32) × 5/9 = -17.78°C

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3 years ago

What is 582,030 in word form

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4 years ago

When purchasing bulk orders of batteries, a toy manufacturer uses this acceptance sampling plan: Randomly select and test 48 b

olga_2 [115]

Answer:

a) the probability that this whole shipment will be accepted is 0.8731

b) Almost all shipments (87.31% of the shipments) would be accepted

Step-by-step explanation:

a) Given that:

p = 1% = 0.01

n = 48

Binomial probability states that

$P(X=x) = \frac{n!}{x!(n-x)!} .p^{x}(1-p)^{n-x}$

Addition rule for mutually exclusive events is:

P(A or B) = P(A) + P(B)

To get the probability that this whole shipment will be accepted we evaluate at x = 0, 1, 2

$P(X=0) = \frac{48!}{0!(48-0)!} .0.01^{0}(1-0.01)^{48-0}=0.6173\\P(X=1) = \frac{48!}{1!(48-1)!} .0.01^{1}(1-0.01)^{48-1}=0.1848\\P(X=2) = \frac{48!}{2!(48-2)!} .0.01^{2}(1-0.01)^{48-2}=0.071$

Using addition rule:

P(X ≤ 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.6173 + 0.1848 + 0.071 = 0.8731

the probability that this whole shipment will be accepted is 0.8731

b) Almost all shipments (87.31% of the shipments) would be accepted

5 0

3 years ago