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artcher [175]
2 years ago
14

Pls answer this correct ;( don't answer it nonsenses. :) Thanks!

Mathematics
1 answer:
Eduardwww [97]2 years ago
5 0

Answer:

jennifer won 15 time and mark won 24

if the answer is wrong i am really sorry

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Write an equation of the hyperbola given that the center is at (2, -3), the vertices are at (2, 3) and (2, - 9), and the foci ar
zavuch27 [327]
Check the picture below.

so, the hyperbola looks like so, clearly a = 6 from the traverse axis, and the "c" distance from the center to a focus has to be from -3±c, as aforementioned above, the tell-tale is that part, therefore, we can see that c = 2√(10).

because the hyperbola opens vertically, the fraction with the positive sign will be the one with the "y" in it, like you see it in the picture, so without further adieu,

\bf \textit{hyperbolas, vertical traverse axis }
\\\\
\cfrac{(y- k)^2}{ a^2}-\cfrac{(x- h)^2}{ b^2}=1
\qquad 
\begin{cases}
center\ ( h, k)\\
vertices\ ( h,  k\pm a)\\
c=\textit{distance from}\\
\qquad \textit{center to foci}\\
\qquad \sqrt{ a ^2 + b ^2}\\
asymptotes\quad  y= k\pm \cfrac{a}{b}(x- h)
\end{cases}\\\\
-------------------------------

\bf \begin{cases}
h=2\\
k=-3\\
a=6\\
c=2\sqrt{10}
\end{cases}\implies \cfrac{[y- (-3)]^2}{ 6^2}-\cfrac{(x- 2)^2}{ b^2}=1
\\\\\\
\cfrac{(y+3)^2}{ 36}-\cfrac{(x- 2)^2}{ b^2}=1
\\\\\\
c^2=a^2+b^2\implies (2\sqrt{10})^2=6^2+b^2\implies 2^2(\sqrt{10})^2=36+b^2
\\\\\\
4(10)=36+b^2\implies 40=36+b^2\implies 4=b^2
\\\\\\
\sqrt{4}=b\implies 2=b\\\\
-------------------------------\\\\
\cfrac{(y+3)^2}{ 36}-\cfrac{(x- 2)^2}{ 2^2}=1\implies \cfrac{(y+3)^2}{ 36}-\cfrac{(x- 2)^2}{ 4}=1

3 0
3 years ago
Pleaseeeeeeeeeeeeee helppppppppppp
sergeinik [125]

Answer:

Step-by-step explanation:

8) (5x + 23) + (17x - 41) = 180

                             22x = 198

                                  x = 9

      arc JK    5(9) + 23 = 68°

     arc MJ    17(9) - 41 = 112°

     arc LMK  360 - 112 = 248

9) 8x + (21x - 12) + (10x + 9) + 90 = 360

                                             39x = 273

                                                  x = 7

                    arc WX    21(7) - 12 = 135°

                    arc YW    90 + 8(7) = 146°

                      arc YX    10(7) + 9 = 79°

                  arc VXW  360 - 8(7) = 304°

6 0
2 years ago
A right-angled triangle has shorter side lengths exactly c^2-b^2 and 2bc units respectively, where b and c are positive real num
yKpoI14uk [10]

Answer: hypotenuse = c^{2} + b^{2}

Step-by-step explanation: Pythagorean theorem states that square of hypotenuse (h) equals the sum of squares of each side (s_{1},s_{2}) of the right triangle, .i.e.:

h^{2} = s_{1}^{2} + s_{2}^{2}

In this question:

s_{1} = c^{2}-b^{2}

s_{2} = 2bc

Substituing and taking square root to find hypotenuse:

h=\sqrt{(c^{2}-b^{2})^{2}+(2bc)^{2}}

Calculating:

h=\sqrt{c^{4}+b^{4}-2b^{2}c^{2}+(4b^{2}c^{2})}

h=\sqrt{c^{4}+b^{4}+2b^{2}c^{2}}

c^{4}+b^{4}+2b^{2}c^{2} = (c^{2}+b^{2})^{2}, then:

h=\sqrt{(c^{2}+b^{2})^{2}}

h=(c^{2}+b^{2})

Hypotenuse for the right-angled triangle is h=(c^{2}+b^{2}) units

3 0
3 years ago
What is value of the 8 in 325,785,901
Inessa [10]
Ten thousands

if you're speaking of place value?
6 0
3 years ago
Read 2 more answers
A home has dimensions of 35 feet by 57 feet that include an attached 24-foot by 22-foot garage and a 200-square-foot screened po
tekilochka [14]
35*57 = 1995
1995 - ((24*22)+200) = 1267
1267 is your answer.
8 0
3 years ago
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