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2 years ago

Which represents potential engery

1 answer:

8 0

Potential energy is restored energy so it would be when you are on a swing because when you swing forward and get high ground you stop for a moment and that is potential energy until you swing backward which is kinetic energy

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While in Europe, if you drive 109 km per day, how much money would you spend on gas in one week if gas costs 1.10 euros per lite

MrRissso [65]

Answer:

The amount is $x = 113.3 \ dollars$

Explanation:

From the question we are told that

The distance traveled per day is $l = 109\ km = \frac{109}{1.609} = 67.74 \ mi$

The cost of one liter is $c = 1.10 \ euros/liter = 1.10 * 1.26 = 1.36 \ dollars/liter$

The car's gas mileage is $b = 22.0 \ mi/gal$

Generally the amount of distance covered in one week is evaluated as

$z = 67.74 * 7$

$z = 474.18 \ mi$

The amount of gas used in one week by the car is mathematically represented as

$k = \frac{ z}{ b}$

=> $k = \frac{ 474.18}{ 22}$

=> $k = 22 \ gal$

converting to liters

$k = 22 * 3.78541=83.28 \ liters$

Thus the amount spent on gas in one week is

$x = k * c$

=> $x = 83.28 * 1.36$

=> $x = 113.3 \ dollars$

5 0

3 years ago

Calculate the number of grams of oxygen gas in a 24L container at STP

romanna [79]

There are 34 g of oxygen in the container.

We can use the Ideal Gas Law to solve this problem.

$pV = nRT$

But $n = \frac{m}{M}$ , so

$pV = \frac{m}{M}RT$ and

$m = \frac{pVM}{RT}\\$

STP is 0 °C and 1 bar, so

$m = \frac{\text{1 bar} \times \text{24 L} \times 32.00 \text{ g}\cdot\text{mol}^{-1}}{\text{0.083 14 } \text{bar}\cdot\text{L}\cdot\text{K}^{-1}\text{mol}^{-1}\times\text{273.15 K} } = \textbf{34 g}\\$

7 0

3 years ago

2.2 Chromium has four naturally-occurring isotopes: 4.34% of 50Cr, with an atomic weight of 49.9460 amu; 83.79% of 52Cr, with an

shutvik [7]

Answer:

Average atomic mass = 51.9963 amu

Explanation:

Given data:

Abundance of Cr⁵⁰ with atomic mass= 4.34% , 49.9460 amu

Abundance of Cr⁵² with atomic mass = 83.79%, 51.9405 amu

Abundance of Cr⁵³ with atomic mass =9.50%, 52.9407 amu

Abundance of Cr⁵⁴ with atomic mass = 2.37%, 53.9389 amu

Average atomic mass = 51.9963 amu

Solution:

Average atomic mass = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass +....n) / 100

Average atomic mass = (4.34×49.9460)+(83.79×51.9405) +(9.50×52.9407)+ (2.37×53.9389) / 100

Average atomic mass = 216.7656 + 4352.0945 + 502.9367 +127.8352 / 100

Average atomic mass = 5199.632 / 100

Average atomic mass = 51.9963 amu

4 0

2 years ago

How many electrons may be accommodated in the first three energy levels?

viktelen [127]

Each shell can contain only a fixed number of electrons: The first shell can hold up to two electrons, the second shell can hold up to eight (2 + 6) electrons, the third shell can hold up to 18 (2 + 6 + 10) and so on. Some points will be nice

3 0

2 years ago

Read 2 more answers

Please answer with an actual answer and not just put a random word ^-^

WARRIOR [948]

Which eclipse was modeled when the large ball was between the small ball and the light?

The model is a "Lunar Eclipse" (If it was talking about the earth, then yes, it is a lunar eclipse).

Which eclipse was modeled when the small ball was between the large ball and the light?

The model is a "Solar Eclipse".

What does the large ball represent?

The earth.

What does the small ball represent?

The moon.

What does the light source represent?

The sun.

Hope this helps!~ <3

(I can't draw so sorry.)

6 0

2 years ago