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ozzi
3 years ago
13

How many grams of KNO3, are needed to create 675.0 mL with a concentration of 1.71 M

Chemistry
1 answer:
valkas [14]3 years ago
4 0

Answer:

Бардык белгилүү авиация мыйзамдарына ылайык, аары учуу мүмкүнчүлүгү жок. Канаттары өтө эле кичинекей, семиз денесин чече албайт. Албетте, аары баары бир учат. Себеби аарылар адам мүмкүн эмес деп эсептеген нерсеге маани бербейт.

Explanation:

Канаттары өтө эле кичинекей, семиз денесин чече албайт. Албетте, аары баары бир учат. Себеби аарылар адам мүмкүн эмес деп эсептеген нерсеге маани бербейт.

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Answer: the hydrosphere

Explanation:

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3 years ago
Write the formula for the conjugate base for the following acids. <br>Thank you ​
Llana [10]

Answer:

See the answer and explanation below , please.

Explanation:

A conjugate base is defined as that formed after an acid donates its proton.

For each article, a continuation of the conjugate bases (highlighted in bold), for dissociation in water:

a) HF + H20 --> F- + H30+      

b) H20+ H20 --> OH-  + H30+

C)H2PO3-  + H20--> HPO3 2-   + H30+

d) HSO4- + H20 -->  SO4 2- + H30+

E) HCL02 + H20 --> CLO02 -   + H30+

7 0
3 years ago
Read 2 more answers
What is the net ionic equation for the reaction that occurs when aqueous solutions of koh and zncl2 are mixed?
Mademuasel [1]

Answer:

Net ionic equation:

Zn²⁺(aq)  +   2OH⁻(aq)     →    Zn(OH)₂(s)

Explanation:

Chemical equation:

ZnCl₂ + KOH    →   KCl  + Zn(OH)₂

Balanced chemical equation:

ZnCl₂ + 2KOH    →   2KCl  +Zn(OH)₂

Ionic equation;

Zn²⁺(aq)  + 2Cl⁻(aq)  + 2K⁺(aq)  +  2OH⁻(aq)     →   2K⁺(aq)  + 2Cl⁻(aq)   +Zn(OH)₂(s)

Net ionic equation:

Zn²⁺(aq)  +   2OH⁻(aq)     →    Zn(OH)₂(s)

The K⁺  and Cl⁻  are spectator ions that's why these are not written in net ionic equation. The  Zn(OH)₂ can not be splitted into ions because it is present in solid form.

Spectator ions:

These ions are same in both side of chemical reaction. These ions are cancel out. Their presence can not effect the equilibrium of reaction that's why these ions are omitted in net ionic equation.  

5 0
3 years ago
During the combustion of methane (CH4), one mole of methane gas combines with two moles of oxygen gas (O2) to produce one mole o
astraxan [27]

Answer:

CH4(g) +2O2____ CO2(g) +2H2O (l)

3 0
3 years ago
Need help ASAP!<br><br> How many moles of sodium nitrate are in 0.25 L of 1.2 M NaNO3 solution?
Setler79 [48]

Answer:

\boxed {\boxed {\sf 0.3 \ mol \ NaNO_3}}

Explanation:

Molarity is a measure of concentration in moles per liter.

molarity= \frac{moles \ of \ solute}{liters \ of \ solution}

The molarity of the solution is 1.2 M NaNO₃ or 1.2 moles NaNO₃ per liter. There are 0.25 liters of the solution. The moles of solute are unknown, so we can use x.

  • molarity= 1.2 mol NaNO₃/L
  • liters of solution=0.25 L
  • moles of solute =x

1.2 \ mol \ NaNO_3/L= \frac{x}{0.25 \ L}

We are solving for x, so we must isolate the variable, x. It is being divided by 0.25 liters. The inverse of division is multiplication, so we multiply both sides by 0.25 L.

0.25 \ L *1.2 \ mol \ NaNO_3/L=\frac{x}{0.25 \ L} *0.25 \ L

0.25 \ L *1.2 \ mol \ NaNO_3/L=x

The units of liters cancel, so we are left with the units moles of sodium nitrate.

0.25  *1.2 \ mol \ NaNO_3=x

0.3 \ mol \ NaNO_3=x

There are 0.3 moles of sodium nitrate.

3 0
2 years ago
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