Question

HELPP! pls

Answer 1

Answer:

"2.48 mole" of H₂ are formed. A further explanation is provided below.

Explanation:

The given values are:

Mole of Al,

= 3.22 mole

Mole of HBr,

= 4.96 mole

Now,

(a)

The number of mole of H₂ are:

⇒  $\frac{Mole \ of \ H_2}{3} =\frac{Mole \ of HBr}{6}$

or,

⇒  $Mole \ of \ H_2=\frac{1}{2}\times Mole \ of \ HBr$

⇒                      $=\frac{1}{2}\times 4.96$

⇒                      $=2.48 \ mole$

(b)

The limiting reactant is:

= $HBr$

(c)

The excess reactant is:

= $Al$