Commonly the sea walls are used for preventing damage from tsunami. A special type of device is also used for detecting the tsunami called floating device.
<h3>
What are the technologies that could help reduce the damage from a tsunami?</h3>
Commonly seawalls are used for preventing damage from tsunamis. There is a network which is used for detecting the earthquake and tsunami and that network is known as Seismological network. This network helps the people to know about the earthquakes and tsunamis and reduces the damages of earthquakes and tsunamis.
The engineers also design a special type of special buoys which is also known as floating devices, these devices are placed near the coastal areas from where the tsunamis can be detected easily.
So we can conclude that commonly the sea walls are used for preventing damage from tsunami. A special type of device is also used for detecting the tsunami called floating device.
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Answer:
c
Explanation:
oxygen is lost electrons are added in oxidation state is decreased
There are 2.32 x 10^6 kg sulfuric acid in the rainfall.
Solution:
We can find the volume of the solution by the product of 1.00 in and 1800 miles2:
1800 miles2 * 2.59e+6 sq m / 1 sq mi = 4.662 x 10^9 sq m
1.00 in * 1 m / 39.3701 in = 0.0254 m
Volume = 4.662 x 10^9 m^2 * 0.0254 m
= 1.184 x 10^8 m^3 * 1000 L / 1 m3
= 1.184 x 10^11 Liters
We get the molarity of H2SO4 from the concentration of [H+] given by pH = 3.70:
[H+] = 10^-pH = 10^-3.7 = 0.000200 M
[H2SO4] = 0.000100 M
By multiplying the molarity of sulfuric acid by the volume of the solution, we can get the number of moles of sulfuric acid:
1.184 x 10^11 L * 0.000100 mol/L H2SO4 = 2.36 x 10^7 moles H2SO4
We can now calculate for the mass of sulfuric acid in the rainfall:
mass of H2SO4 = 2.36 x 10^7 moles * 98.079 g/mol
= 2.32 x 10^9 g * 1 kg / 1000 g
= 2.32 x 10^6 kg H2SO4
The total pressure of the mixture of gases is
equal to the sum of the pressure of each gas as if it is alone in the
container. The partial pressure of a component of the mixture is said to be
equal to the product of the total pressure and the mole fraction of the
component in the mixture.<span>
Partial pressure of hydrogen gas = 1.24 atm x
.25 = 0.31 atm
<span>Partial pressure of the remaining = 1.24 atm x
(1-.25) = 0.93 atm </span></span>
