2/3x=26
multiply both sides by 3/2 to get x by itself
2/3x(3/2)=26 (3/2)
Cross out 2s and 3s. Divide by 2 and 3.
Then becomes 1*1*1*1*x=x
26(3/2)
Cross out 26 and 2. Divide by 2.
26/2=13
2/2=1
13*3=39
Answer:
x=39
If x^2+bx+16 has at least one real root, then the equation x^2+bx+16=0 has at least one solution. The discriminant of a quadratic equation is b^2-4ac and it determines the nature of the roots. If the discriminant is zero, there is exactly one distinct real root. If the discriminant is positive, there are exactly two roots. The discriminant of <span>x^2+bx+16=0 is b^2-4(1)(16). The inequality here gives the values of b where the discriminant will be positive or zero:
b^2-4(1)(16) ≥ 0
</span><span>b^2-64 ≥ 0
(b+8)(b-8) </span><span>≥ 0
The answer is that all possible values of b are in the interval (-inf, -8]∪[8,inf) because those are the intervals where </span>(b+8)(b-8) is positive.
You would use 1.07 for that
Answer:
Step-by-step explanation:
Volume of a cone= ⅓πr²h
=⅓×3.142×5²×6
= 157cm²
1,325-35=1,290
50x25=1,250 50x26=1,300
25 months