<span>Answer 61 73-66= 7 21-13 = 8 ?? -52= 9 20-10 = 10 ??=61</span>
Answer:
the asymptote would be zero because the graph is approaching zero, but never actually touches it.
3:4 = G:B
1:5 = Mr. Smith's class: 7th Grade
2:7= 7th: Middle school
12 girls = 3 units
1 unit = 12/3= 4
Boys = 4x4= 16
<em>Whole class = 28 students</em>
Class : Grade = 1:5 <em> 7 = number of units in Mr. Smith's class</em>
28 = 1 unit
5 units= 28x5= 140 <em>There are 140 kids in the grade</em>
140 = 2 units
1 unit = 140/2= 70
70x7=490
<u><em>There are 490 students in the whole grade</em></u>
Answer:
8
Step-by-step explanation:
4 ÷ 1/2
~Turn the 4 into a fraction
4/1 ÷ 1/2
~Copy Dopt Flip
4/1 * 2/1
~Multiply
8/1
~Simplify
8
Best of Luck!
If I were to tell a kid how to use the formula (the SA of a pyramid it looks like):
First, find the area of the base of the figure, using length times width.
Next, find the perimeter of the base by adding up the length of each side of the base.
Multiply the perimeter of the base by the slant height of the figure, which is the line on the side of the figure that is diagonal.
Divide the answer you got from multiplying the perimeter of the base times the slant height of the base by 2.
Now add up the area of the base of the figure with the answer you just got by dividing the perimeter of the base times the slant height by 2.
That is how you use the formula: SA = B + 1/2(P · l)