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Deffense [45]
4 years ago
6

Richard & Tanjeev share a lottery win of £5650 in the ratio 4 : 1. Richard then shares his part between himself, his wife &a

mp; their son in the ratio 6 : 3 : 1. How much more does his wife get over their son?
Mathematics
1 answer:
lidiya [134]4 years ago
4 0

Answer:

Answer is 904

Refer below.

Step-by-step explanation:

5650 total,

And 4:1 which adds up and make 5. So,

5x = 5650

x=5650/5

x=1130

As pichard part is 4:1 so his part is 4 overall the money so,

Richard got 4x = 4 × 1130 = 4520

4520 now dividing in 6:3:1

10a = 4520

A= 452

Wife amount is 3a = 3 ×452 = 1356

Son is 1a so its,

Son = 452

Minus= 1356 -452 = 904

Wife got 904 more than son

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Standard Form:
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3 years ago
What is the period and midline?
OverLord2011 [107]
\bf \qquad \qquad \qquad \qquad \textit{function transformations}&#10;\\ \quad \\&#10;% function transformations for trigonometric functions&#10;\begin{array}{rllll}&#10;% left side templates&#10;f(x)=&{{  A}}cos({{  B}}x+{{  C}})+{{  D}}&#10;\\ \quad \\&#10;&#10;\end{array}\qquad

\bf \begin{array}{llll}&#10;% right side info&#10;\bullet \textit{ stretches or shrinks}\\&#10;\quad \textit{horizontally by amplitude } |{{  A}}|\\&#10;\bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\&#10;\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\&#10;\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\&#10;\bullet \textit{vertical shift by }{{  D}}\\&#10;\qquad if\ {{  D}}\textit{ is negative, downwards}\\&#10;\qquad if\ {{  D}}\textit{ is positive, upwards}\\&#10;&#10;&#10;\end{array}

\bf \begin{array}{llll}&#10;\bullet \textit{function period}\\&#10;\qquad \frac{2\pi }{{{  B}}}\ for\ cos(\theta),\ sin(\theta),\ sec(\theta),\ csc(\theta)\\&#10;\qquad \frac{\pi }{{{  B}}}\ for\ tan(\theta),\ cot(\theta)&#10;\end{array}&#10;

so if you notice yours \bf \begin{array}{llll}&#10;3.2cos&\left( \frac{5}{3}\theta \right)+&6.1\\&#10;&\ \uparrow&\uparrow \\&#10;&B&D &#10;\end{array}

now.. normally the function \bf 3.2cos&\left( \frac{5}{3}\theta \right)
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now, with D = 6.1, that moves the midline  up vertically that much

now.. the period, well, B = 5/3, normal period of cosine is 2\pi
so, the new period will be \bf \cfrac{2\pi }{B}\implies \cfrac{2\pi }{\frac{5}{3}}\implies \cfrac{6\pi }{5}

notice the picture below
the vertical shift by the D component, or 6.1, moved the midline to y = 6.1 :)

6 0
3 years ago
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mixas84 [53]

Answer:

y=-\frac{1}{3}x+-7

Step-by-step explanation:

The graph shows a negative slope with 3 units in between each point.

Every 3 x-units, the y-unit goes up once.

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3 years ago
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