Mechanical energy
I think
Explanation:
We start by using the conservation law of energy:

or

Simplifying the above equation, we get

We can rewrite this as

Note that the expression inside the parenthesis is simply the acceleration due to gravity
so we can write

where
is the launch velocity.
Answer:
Pressure of the gas is greater than the vapor pressure, therefore all the solid will not sublime.
Explanation:
To solve this problem we use ideal gas equation.
PV =nRT
If Presure of the gas (P) is greater than vapor pressure (56.5 atm), all the solid will not sublime. But If P < 56.5 atm, all of it will sublime.
where;
P is pressure of the gas in atm
V is volume of gas in Litre
T is absolute temperature of the gas in Kelvin
n is number of gas moles
R is ideal gas constant or Boltzmann constant = 0.082057 L atm K⁻¹ mol⁻¹
Given T = 20 °C = 273 + 20 = 293K
Volume = 0.25L
n = Reacting mas (m)/Molar mass(M)
Molar mass of CO₂ = 12 + (16X2) = 12+32 = 44g/mol
Reacting mass = 10g
n = m/M ⇒ 10/44
n = 0.2273
PV =nRT ⇒ P = nRT/V
P = (0.2273X0.082057 X293)/0.25
P = 21.8596 atm
Therefore, since Pressure of the gas is greater than the vapor pressure, all the solid will not sublime.