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Dmitry [639]
4 years ago
10

A microwave oven produces electromagnetic radiation with a wavelength of 12.2 cm and a power of 760 W. Calculate the number of m

icrowave photons produced by the oven per second.
Physics
1 answer:
Fiesta28 [93]4 years ago
5 0

Answer:

The number of microwave photons produced by the oven per second, is 4.665 x 10²⁶ photons / s

Explanation:

Given;

wavelength of the electromagnetic radiation, λ = 12.2 cm = 0.122 m

power of the photon, P = 760 W = 760 J/s

The energy of a single photon of the radiation is given as;

E = hf\\\\E = h(\frac{c}{\lambda} )\\\\E = 6.626*10^{-34}(\frac{3*10^{8}}{0.122} )\\\\E = 1.629*10^{-24} \ J / photon \\\\

The number of microwave photons produced by the oven per second, is given as;

n = \frac{760 \ J/s}{1.629*10^{-24} \ J/photon} \\\\n = 4.665*10^{26} \ photons / s\

Therefore, the number of microwave photons produced by the oven per second, is 4.665 x 10²⁶ photons / s

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An observer measures the length (L), width (w), and height (h) of a box while stationary relative to the box. The observer then
Elenna [48]

Answer:

b. less than w.

Explanation:

In this question, the application of length contraction is what helps us come to our conclusion. When an object moves very fast (relative to the observer), the length of the object seems to be smaller than it actually is (again, for the observer).

This is supported by the length contraction equation below:

L = L_0\sqrt{1-\frac{v^2}{c^2} }

Here, L is the observed length

L_0 is the original length of the object

v is the relative speed between the object and the observer

and c is the speed of light

Using this equation, we can see that as the speed between the object and the observer is increased to be close to that of light, the square root in the equation gives us values less than 1.0

This effectively decreases the length that is observed.

8 0
3 years ago
A circular loop of wire with 15 turns, radius 0.129 m and resistance 0.251 Ohms is connected to a 16.7 V power supply. The magne
Licemer1 [7]

The magnetic field at the center of the circular loop is 3.24 x 10⁻⁴ T.

<h3>Current in the wire</h3>

The current in the wire is calculated as follows;

V = IR

I = V/R

I = 16.7/0.251

I = 66.53 A

<h3>Magnetic field at the center of the loop</h3>

The magnetic field at the center of the circular loop is calculated as follows;

B = \frac{\mu_0 I}{2R} \\\\B = \frac{4\pi \times 10^{-7} \times66.53 }{2\times 0.129} \\\\B = 3.24 \times 10^{-4} \ T

Learn more about magnetic field here: brainly.com/question/7802337

3 0
3 years ago
Which electromagnetic waves have the greatest frequencies? ​
Ket [755]

Answer:

Gamma rays

Explanation:

Gamma rays have the highest frequency in the electro magnetic spectrum

3 0
3 years ago
explain why if charge cannot be created or destroyed, electrically neutral objects can become electrically charged
natali 33 [55]
Charge is actually either excessive number or electrons or shortage of them.
as you can't destroy the electron or create it - you can't destroy or create charge 

5 0
3 years ago
Experimenting with free fall, Mariana observes that her baseball takes 1.5 s to travel the last 30m before hitting the ground. F
Art [367]

Answer:

37.8 m

Explanation:

At point 0, the ball is at height y₀.

At point 1, the ball is at height 30 m.

At point 2, the ball is at height 0 m.

Given:

y₁ = 30 m

y₂ = 0 m

v₀ = 0 m/s

a = -10 m/s²

t₂ − t₁ = 1.5 s

Find: y₀

Use constant acceleration equation.

y = y₀ + v₀ t + ½ at²

Evaluate at point 1.

y₁ = y₀ + v₀ t₁ + ½ at₁²

30 m = y₀ + (0 m/s) t₁ + ½ (-10 m/s²) t₁²

30 = y₀ − 5t₁²

Evaluate at point 2.

y₂ = y₀ + v₀ t₂ + ½ at₂²

0 m = y₀ + (0 m/s) t₂ + ½ (-10 m/s²) t₂²

0 = y₀ − 5t₂²

y₀ = 5t₂²

Substitute:

y₀ = 5 (1.5 + t₁)²

y₀ = 5 (2.25 + 3t₁ + t₁²)

y₀ = 11.25 + 15t₁ + 5t₁²

30 = 11.25 + 15t₁ + 5t₁² − 5t₁²

30 = 11.25 + 15t₁

t₁ = 1.25

30 = y₀ − 5t₁²

30 = y₀ − 5(1.25)²

y₀ ≈ 37.8

4 0
4 years ago
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