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Gekata [30.6K]
3 years ago
7

A satellite is to be launched into an orbit of radius,r Show that v = 2gr, where V is the

Physics
1 answer:
Snezhnost [94]3 years ago
6 0

Explanation:

We start by using the conservation law of energy:

\Delta{K} + \Delta{U} = 0

or

\dfrac{1}{2}mv^2 - G\dfrac{mM}{r} = 0

Simplifying the above equation, we get

v^2 = 2G\dfrac{M}{r}

We can rewrite this as

v^2 = 2\left(G\dfrac{M}{r^2}\right)r

Note that the expression inside the parenthesis is simply the acceleration due to gravity g so we can write

v^2 = 2gr

where v is the launch velocity.

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The visible surface of the Sun, which is also the deepest layer we can see with our eyes, is in which region of the Sun?
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It is the photosphere
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3 years ago
Scientists use the micron as a unit of length for very
r-ruslan [8.4K]

Answer:

1 micron = 1.00E-6  m   is one way

1.00^-6 m    is another but is not usually considered scientific notation, but                      

                   often convenient to use.

6 0
3 years ago
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seraphim [82]

Try this option, the answers are marked with colour.

8 0
3 years ago
In doing a load of clothes, a clothes dryer uses 16 A of current at 240 V for 45 min. A personal computer, in contrast, uses 2.7
EastWind [94]

Answer:

(a) Total time will be 8.05 hour

(B) Total cost will be $417.6                

Explanation:

We have given dryer uses 16 A of current so current i = 16 A

Voltage V = 240 volt

Time t = 45 minutes =45×60 = 2700 sec

So power P = VI = 240×16 = 3840 W

So energy E = power×time = 3840×45×60 = 9396 KJ

(A) Now current in the computer i = 2.7 A

Voltage V = 120 V

So power P = 120×2.7 = 324 W

Now computer is using energy of dryer

So time by which it will use energy is t=\frac{9396000}{324}=29000sec=8.05hour

So time will be 8.05 hour

(b) Cost per kilowatt is $0.12

So total cost =3480×0.12 = $417.6

4 0
3 years ago
What is the radius of a tightly wound solenoid of circular cross-section that has 180turns if a change in its internal magnetic
Nata [24]

Answer:

Radius of cross section, r = 0.24 m

Explanation:

It is given that,

Number of turns, N = 180

Change in magnetic field, \dfrac{dB}{dt}=3\ T/s

Current, I = 6 A

Resistance of the solenoid, R = 17 ohms

We need to find the radius of the solenoid (r). We know that emf is given by :

E=N\dfrac{d\phi}{dt}

E=N\dfrac{d(BA)}{dt}

Since, E = IR

IR=NA\dfrac{dB}{dt}

A=\dfrac{IR}{N.\dfrac{dB}{dt}}

A=\dfrac{6\ A\times 17\ \Omega}{180\times 3\ T/s}

A=0.188\ m^2

or

A=0.19\ m^2

Area of circular cross section is, A=\pi r^2

r=\sqrt{\dfrac{A}{\pi}}

r=\sqrt{\dfrac{0.19}{\pi}}

r = 0.24 m

So, the  radius of a tightly wound solenoid of circular cross-section is 0.24 meters. Hence, this is the required solution.

5 0
3 years ago
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