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Kazeer [188]
3 years ago
9

The normal monthly precipitation (in inches) for August is listed for 20 different U.S. cities. Find the mean of the data. 3.5 1

.6 2.4 3.7 4.1 3.9 1.0 3.6 4.2 3.4 3.7 2.2 1.5 4.2 3.4 2.7 0.4 3.7 2.0 3.6 Group of answer choices 2.94 in. 2.80 in. 3.09 in. 3.27 in.
Mathematics
1 answer:
Burka [1]3 years ago
5 0

Answer:

The correct answer is 2.94 in.

Step-by-step explanation:

The monthly precipitation for August in 20 different U.S. cities are observed in inches.

The data is given by: 3.5, 1.6, 2.4, 3.7, 4.1, 3.9, 1.0, 3.6, 4.2, 3.4, 3.7, 2.2, 1.5, 4.2, 3.4, 2.7, 0.4, 3.7, 2.0 and 3.6.

We intend to find the mean of the given data.

Therefore mean of the precipitation is ∑data ÷ 20 = \frac{58.8}{20} = 2.94 inches.

Thus the mean of the data is 2.94 inches.

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What's 92010÷7X01910​
Nostrana [21]

Answer:

6.8818249813

Step-by-step explanation:

I didn't really get the problem but basically, according to "pemdas" you have to multiply 7x1910 and that would be 13370 and next you would do 92010 divided by 13370 which is 6.8818249813.

4 0
3 years ago
Pls remember to give your answer in metres
spin [16.1K]
Answer: 500m

Explanation:
If the scale of the drawing is 1:500 then the real playground should be 500:1 which is 500m
5 0
3 years ago
The graph of a quadratic function contains the points
masya89 [10]

Answer:

Shawn is correct.

Step-by-step explanation:

Let the quadratic function is g(x) = a(x - h)² + k

Here (h, k) is the vertex of the parabola.

Since this parabola passes through (0, 0), (1, 9) and (-1, 9), axis of symmetry is x = 0 and the vertex is (0, 0).

Therefore, equation of the parabola will be,

g(x) = a(x - 0)²+ 0

g(x) = ax²

for a point (1, 9) which lies on the graph,

9 = a(1)²

a = 9

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Therefore, f(x) is vertically stretched by a factor of 9 to form g(x).

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3 0
3 years ago
When x pounds of force is applied to one end of a lever that is L feet long, the resulting force y on the other end is
nadezda [96]
The question is worded poorly, but it looks like you have a lever in equilibrium, with a force x at a distance d from the fulcrum, and a force y at a distance L - d from the fulcrum. You already have the equilibrium formula for this situation:

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3 0
2 years ago
Find the distance between points P(5, 1) and Q(1, 3) to the nearest tenth.
bonufazy [111]

Answer:

Idk if its multiple choice but you can do 1 of 2 ways theres using distance formula =√(5-3)sq+(1-4)sq

=√4+9

=√13 <--

or

3.6 units

Given: The two points that are P(5,1) and Q(3,4).

To find: The distance between these two points.

Solution: It is given that there are two points that are P(5,1) and Q(3,4).

The distance between these two points can be found out as using the distance formula that is: 3.6

Thus, the distance between the given two points is 3.6 units.

So you choose 13 or 3.6 Hope this helps :)

3 0
3 years ago
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