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sweet-ann [11.9K]
3 years ago
7

What is 1 5/12 - 3 A. 2 5/12B. 2 7/12C. 1 5/12D. 1 7/12​

Mathematics
1 answer:
Savatey [412]3 years ago
6 0

Answer:

D option is correct

=  - 1  7/12

Step-by-step explanation:

1 5/12 - 3

= 17/12 - 3

=  (17-36) / 12

= - 19/12

= - 1  7/12

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Two cars start from the same place at the same time One car travels west at 70 miles per hour and another travels east at 20 mil
vichka [17]

<em>Answer:360 hours</em>

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<em>Step-by-step explanation:You have to add to get you answer.I will show you how I got 360:</em>

<em>70+20=90</em>

<em>90+20=110</em>

<em>110+250=360</em>

<em>Your answer is: 360 hours</em>

hope this is helpful :)

4 0
3 years ago
Trevor says the figure B is a scaled copy of figure 8 because figure B is three times larger than figure A
yanalaym [24]

Answer:

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Step-by-step explanation:

3 0
3 years ago
Write each product in standard form. (y+ 9)(y+ 9)
Alla [95]

Answer:

y² + 18y + 81

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Algebra I</u>

  • Terms/Coefficients
  • Expand by FOIL (First Outside Inside Last)

Step-by-step explanation:

<u>Step 1: Define</u>

(y + 9)(y + 9)

<u>Step 2: Expand</u>

  1. FOIL:                                        y² + 9y + 9y + 81
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3 0
3 years ago
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adelina 88 [10]
I should be on the black dot ☺️

3 0
3 years ago
A large mixing tank initially contains 1000 gallons of water in which 30 pounds of salt have been dissolved. Another brine solut
serg [7]

Answer:

(B)\dfrac{dA}{dt}=8-0.004A

Step-by-step explanation:

Volume of fluid in the tank =1000 gallons

Initial Amount of Salt in the tank, A(0)= 30 pounds

Incoming brine solution of concentration 2 pounds of salt per gallon is pumped in at a rate of 4 gallons per minute.

Rate In=(concentration of salt in inflow)(input rate of brine)

=(2\frac{lbs}{gal})( 4\frac{gal}{min})=8\frac{lbs}{min}

The resulting mixture is pumped out at the same rate, therefore:

Rate Out =(concentration of salt in outflow)(output rate of brine)

=(\frac{A(t)}{1000})( 4\frac{gal}{min})=\frac{A}{250}

Therefore:

The rate of change of amount of salt in the tank,

\dfrac{dA}{dt}=$Rate In-Rate out\\\dfrac{dA}{dt}=8-\dfrac{A}{250}\\\dfrac{dA}{dt}=8-0.004A

5 0
4 years ago
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