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Dafna1 [17]
3 years ago
6

What's the slope and y-intercept?

Mathematics
1 answer:
Ludmilka [50]3 years ago
5 0

Answer:

Slope: -9

y-intercept: (0,5)

Step-by-step explanation:

The slope equation is rise over run. Let's use 2 different points to figure it out. (0,5)(1,-4) So you want to do -4-5 divided by 1-0. The outcome will be -9 over 1. So the answer for slope would be -9. For the y-intercept, you want to find the point on the line where it passes through the y-axis. You would write, (0,5) You wrote 0 for x because it is on the y-axis. I hope this helps!

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A classmate simplified a rational expression below
lara31 [8.8K]
<h2>Part a) </h2><h2>Explain the error in this simplification.</h2>

Given the simplified expression

1-\frac{2}{x-2}=\frac{x+1}{x+2}

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x=1

<u><em>Identifying the Main Error</em></u>

1-\frac{2}{x-2}=\frac{x+1}{x+2}

1-2\left(x+2\right)=\left(x+1\right)\left(x-2\right)   ← ERROR Starts here

<u><em>Here is the Explanation of the Error </em></u>

<u><em /></u>

<u><em /></u>\mathrm{The\:equation\:should\:have\:been\:Multiplied\:by\:LCM=}\left(x-2\right)\left(x+2\right)<em>. </em>In your case you wrongly multiply the equation.

<em><u>CORRECTION</u></em>

<em>HERE IS HOW YOU SHOULD HAVE MULTIPLIED BY </em><em>LCM = (x-2)(x+2):</em>

<em />

1-\frac{2}{x-2}=\frac{x+1}{x+2}

1\cdot \left(x-2\right)\left(x+2\right)-\frac{2}{x-2}\left(x-2\right)\left(x+2\right)=\frac{x+1}{x+2}\left(x-2\right)\left(x+2\right)

\left(x-2\right)\left(x+2\right)-2\left(x+2\right)=\left(x+1\right)\left(x-2\right)

<h2>Part b) </h2><h2>Show your work as you correct the error</h2>

Here is the complete correction of the error.

Considering the expression

1-\frac{2}{x-2}=\frac{x+1}{x+2}

\mathrm{Find\:Least\:Common\:Multiplier\:of\:}x-2,\:x+2:\quad \left(x-2\right)\left(x+2\right)

1\cdot \left(x-2\right)\left(x+2\right)-\frac{2}{x-2}\left(x-2\right)\left(x+2\right)=\frac{x+1}{x+2}\left(x-2\right)\left(x+2\right)

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I hope this helped you.

Brainliest answer would be appreciated. 
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