If the line segment point is D(-5, 10) and E(a,b) and the midpoint of the segment is F(13, -2) that mean
DE= 2*DF
You can directly find the distance of AC
Xdf= Xf-Xd= 13 - (-5)= 18
Ydf= Yf - Yd= -2 - 10= -12
Then add the distance of AB( which is 2*AC) to point D
Xe= a = Xd + 2*Xdf
a= -5 +2*18= 31
Ye= b = Yd + 2Yf
b= 10+ 2*-12= -14
<span>absolute difference between a and b:
|b-a|= </span>|-14-31|= 45
Answer: 
Step-by-step explanation:
You need to set up two cases (Positive case and negative case) and solve for "x".
- POSITIVE CASE IF: 

- NEGATIVE CASE IF: 

Therefore, the solution is:

Answer:
__
0.333
Step-by-step explanation:
you divide 1.00 by 3. The 3s never end.