Your gas bill went up from $120 per month to $150 per month.What is the percent increase of your gas bill

If the area of a circle is 58 square feet, find the circumference

Blizzard [7]

Answer:

C≈27 feet

Step-by-step explanation:

A=πr²

A/π=r²

√A/π =r or –√A/π=r (refused)

then r =√(A/π) =√(58/π) =4.297829403 feet

C=2πr=2π(4.297829403)=27.00405856≈27 feet

7 0

3 years ago

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It appears that people who are mildly obese are less active than leaner people. One study looked at the average number of minute

NemiM [27]

Answer:

a) 10.93% probability that the mean number of minutes of daily activity of the 5 mildly obese people exceeds 420 minutes.

b) 99.22% probability that the mean number of minutes of daily activity of the 5 lean people exceeds 420 minutes.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $\frac{\sigma}{\sqrt{n}}$ .

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Mildly obese

Normally distributed with mean 373 minutes and standard deviation 67 minutes. So $\mu = 373, \sigma = 67$

A) What is the probability that the mean number of minutes of daily activity of the 5 mildly obese people exceeds 420 minutes?

So $n = 5, s = \frac{67}{\sqrt{5}} = 29.96$

This probability is 1 subtracted by the pvalue of Z when X = 410.

$Z = \frac{X - \mu}{s}$

$Z = \frac{410 - 373}{29.96}$

$Z = 1.23$

$Z = 1.23$ has a pvalue of 0.8907.

So there is a 1-0.8907 = 0.1093 = 10.93% probability that the mean number of minutes of daily activity of the 5 mildly obese people exceeds 420 minutes.

Lean

Normally distributed with mean 526 minutes and standard deviation 107 minutes. So $\mu = 526, \sigma = 107$

B) What is the probability that the mean number of minutes of daily activity of the 5 lean people exceeds 420 minutes?

So $n = 5, s = \frac{107}{\sqrt{5}} = 47.86$

This probability is 1 subtracted by the pvalue of Z when X = 410.

$Z = \frac{X - \mu}{s}$

$Z = \frac{410 - 526}{47.86}$

$Z = -2.42$

$Z = -2.42$ has a pvalue of 0.0078.

So there is a 1-0.0078 = 0.9922 = 99.22% probability that the mean number of minutes of daily activity of the 5 lean people exceeds 420 minutes.

7 0

3 years ago

PLEASE help me with the answers!!!

jasenka [17]

100=1,478,300
1000=1,478,000
10,000=1,470,000

5 0

3 years ago

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Which of the following equations are linear or nonlinear?

gavmur [86]

Answer:

1. Linear

2. Nonlinear

3. Linear

4. Linear

5. Nonlinear

Step-by-step explanation:

Thies equation are in the form y=mx+b. Where m is the slope and b is the y-intercept. To solve them you neeed to see the power x is taken to. If the power on x is bigger than 1 than one, then it will curve at some point. This makes 2 and 5 nonlinear

4 0

3 years ago

What is 4.236 divided by 6

neonofarm [45]

0.706 is the answer to your problem

3 0

3 years ago