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Jlenok [28]
3 years ago
8

What is the value of the expression below 81^1/4

Mathematics
2 answers:
ASHA 777 [7]3 years ago
5 0

Answer:

Step-by-step explanation:

81^1/4

And 81 = 3⁴

:- 81^1/4 = 3^(4×1/4)

= 3¹ = 3

Natalija [7]3 years ago
4 0

Answer:

3

Step-by-step explanation:

recall that 81 = 3 x 3 x 3 x 3 = 3⁴

given

81^{\frac{1}{4} }

= ( 3⁴) ^ (1/4)

= 3^{(4)(1/4)}

= 3

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An engineer on the ground is looking at the top of a building the angle of elevation to the top of the building is 22 degrees th
vekshin1
Hello,

tan 22°=450/d
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3 years ago
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Find the approximate area of the circle below. (Use 3 for \pi)
Marat540 [252]

Answer:

75 in²

Step-by-step explanation:

(see attached for reference)

recall that the formula for area of a circle is given by

Area = π r²

where

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simply substituting the values into the equation:

Area = π r²

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3 years ago
Which sum or difference identity would you use to verify that cos (180° - q) = -cos q?
lutik1710 [3]
<h3>Answer: Choice C</h3>

cos(a - b) = cos(a)cos(b) + sin(a)sin(b)

In this case, we'd have a = 180 and b = q, so,

cos(a-b) = cos(a)cos(b) + sin(a)sin(b)

cos(180 - q) = cos(180)cos(q) + sin(180)sin(q)

cos(180 - q) = -1*cos(q) + 0*sin(q)

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8 0
3 years ago
Which transformation causes the described change in the graph of the function y = cos x?
tia_tia [17]
A: a horizontal shrink would be caused by cos 3x.
B: a vertical stretch would be caused by 3 cos x
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defon

Answer:

A=8\pi r^2-\dfrac{49\sqrt{3}x^2}{4}\ un^2.

Step-by-step explanation:

An equilateral triangle with the side 7x units is inscribed in a circle of radius 2r units.

1. The area of the circle is

A_{circle}=2\pi (2r)^2=2\pi \cdot 4r^2=8\pi r^2\ un^2.

2. The area of the equilateral triangle is

A_{\triangle }=\dfrac{(7x)^2\sqrt{3}}{4}=\dfrac{49\sqrt{3}x^2}{4}\ un^2.

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