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Ksivusya [100]
3 years ago
13

A humanities professor assigns letter grades on a test according to the following scheme. A: Top 13% of scores B: Scores below t

he top 13% and above the bottom 60% C: Scores below the top 40% and above the bottom 23% D: Scores below the top 77% and above the bottom 8% F: Bottom 8% of scores Scores on the test are normally distributed with a mean of 70 and a standard deviation of 9.6. Find the minimum score required for an A grade. Round your answer to the nearest whole number, if necessary
Mathematics
1 answer:
Musya8 [376]3 years ago
7 0

Answer:

81

Step-by-step explanation:

Given data:

mean μ = 70.

standard deviation σ, 9.6.

P(Z < 1.123) = 0.13

z = 1.13

Use the z-score formula,

x = z×σ +μ

Substitute the values in the above equation.

x = 1.13 9.6 + 70 = 81

The minimum score required for an A grade is = 81

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Write the following number as ratios of integers
s2008m [1.1K]

Our goal here is to somehow "surgically remove" the repeating part of the number, so let's start by putting the original value in a variable and messing around with it a bit.

We'll let x=7.\overline{6}. We want to cut the 0.\overline{6} bit off completely, so let's create the scalpel that'll let us do that. If x=7.\overline{6}, then we can also say that 10x=76.\overline{6}. Maybe I was lying a bit: the x is our real scalpel here, and 10x is where we'll be making the cut. Mathematically, a "cut" is almost always shorthand for subtraction, so let's see what our operation (cutting x off of 10x) leaves us with:

10x-x=76.\overline{6}-7.\overline{6}\\9x=69

The operation was a success! We can now simply divide either side by 9 to find x = 69/9, which, when reduced by dividing the numerator and denominator by 3, gives us x=23/3

7 0
3 years ago
Scientists modeled the intensity of the sun, I, as a function of the number of hours since 6:00 a.m., h, using the
MAVERICK [17]

The functions are illustrations of composite functions.

<em>The soil temperature at 2:00pm is 67</em>

The given parameters are:

\mathbf{I(h) =\frac{12h - h^2}{36}} ---- the function for sun intensity

\mathbf{T(I) =\sqrt{5000I}} -- the function for temperature

At 2:00pm, the value of h (number of hours) is:

\mathbf{h = 2:00pm - 6:00am}

\mathbf{h = 8}

Substitute 8 for h in \mathbf{I(h) =\frac{12h - h^2}{36}}, to calculate the sun intensity

\mathbf{I(8) =\frac{12 \times 8 - 8^2}{36}}

\mathbf{I(8) =\frac{32}{36}}

\mathbf{I(8) =\frac{8}{9}}

Substitute 8/9 for I in \mathbf{T(I) =\sqrt{5000I}}, to calculate the temperature of the soil

\mathbf{T(8/9) =\sqrt{5000 \times 8/9}}

\mathbf{T(8/9) =\sqrt{4444.44}}

\mathbf{T(8/9) =66.67}

Approximate

\mathbf{T(8/9) =67}

Hence, the soil temperature at 2:00pm is 67

Read more about composite functions at:

brainly.com/question/20379727

5 0
2 years ago
PLEASE HELP MY GROUP
Hoochie [10]

A=1007.27

B=2895.29

C=≈2714.34

D=111.84

6 0
3 years ago
Read 2 more answers
At the end of dinner, equivalant amounts of lasagna in two pans were left.
Oksanka [162]

2/4+2/4 or 1/2+1/2

if there is 2/4 in one pan and 1/2 in another 2/4=1/2

8 0
3 years ago
20 Points! <br><br> Solve for x
Marrrta [24]

Answer:

so all x's have to be added together.

8x+5x+10x+7x=30x

-2+3=1

1dividedby30=30

x=30

hope this helps


7 0
3 years ago
Read 2 more answers
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