:If PQRS is a parallelogram with two adjacent congruent sides, then the quadrilateral yielded becomes a rhombus:
A rhombus is a quadrilateral that has the same properties as a parallelogram but all sides are congruent
Answer:
the lateral area of cone is L=A﹣πr2
the surface area of cone is
6+3x = 2(2) + 2(x)
6+3x = 4 + 2x
-6 -6
3x = -2+2x
-2x -2x
answer:
x = -2
Answer:
-x¹⁴ / 5040
-½ < x < ½
Step-by-step explanation:
f(x) = e^(-x²)
The Taylor series for eˣ centered at 0 is:
eˣ = ∑ (1/n!) xⁿ
Substitute -x²:
e^(-x²) = ∑ (1/n!) (-x²)ⁿ
e^(-x²) = ∑ (1/n!) (-1)ⁿ x²ⁿ
The 14th degree term occurs at n=7.
(1/7!) (-1)⁷ x¹⁴
-x¹⁴ / 5040
ln(1 + x) = ∑ₙ₌₁°° (-1)ⁿ⁺¹ xⁿ / n
If we substitute 4x²:
ln(1 + 4x²) = ∑ₙ₌₁°° (-1)ⁿ⁺¹ (4x²)ⁿ / n
Using ratio test:
lim(n→∞)│aₙ₊₁ / aₙ│< 1
lim(n→∞)│[(-1)ⁿ⁺² (4x²)ⁿ⁺¹ / (n+1)] / [(-1)ⁿ⁺¹ (4x²)ⁿ / n]│< 1
lim(n→∞)│-1 (4x²) n / (n+1)│< 1
4x² < 1
x² < ¼
-½ < x < ½
Answer:
Step-by-step explanation:
Step 1: Flip the equation.
Step 2: Subtract D from both sides.
Step 3: Divide both sides by Dr.
