Answer:
Probability that a sample mean is 12 or larger for a sample from the horse population is 0.0262.
Step-by-step explanation:
We are given that a veterinary researcher takes a random sample of 60 horses presenting with colic. The average age of the random sample of horses with colic is 12 years. The average age of all horses seen at the veterinary clinic was determined to be 10 years. The researcher also determined that the standard deviation of all horses coming to the veterinary clinic is 8 years.
So, firstly according to Central limit theorem the z score probability distribution for sample means is given by;
Z =
~ N(0,1)
where,
= average age of the random sample of horses with colic = 12 yrs
= average age of all horses seen at the veterinary clinic = 10 yrs
= standard deviation of all horses coming to the veterinary clinic = 8 yrs
n = sample of horses = 60
So, probability that a sample mean is 12 or larger for a sample from the horse population is given by = P(
12)
P(
12) = P(
) = P(Z
1.94) = 1 - P(Z < 1.94)
= 1 - 0.97381 = 0.0262
Therefore, probability that a sample mean is 12 or larger for a sample from the horse population is 0.0262.
Answer:
60π
Step-by-step explanation:
2π(3 × 7 ) + 2π (3)^2
Distribute: 2x3x7 and 2x3^2
42π + 18π
That gives 60π.
E+r=
(e=9)
r=1.50)
or 9+1.50=
I think
Answer:
a) decimal 7.222
fraction: 65/9
percentage: 722.22
b) Fraction: 37/5
decimal: 7.4
Percentage: 740
Step-by-step explanation:
Hey there,
AM= 10
180 - 10 = 170.
TC equals 170.
Hope this helps.
~Jurgen