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Roman55 [17]
3 years ago
10

Matter is in a liquid state when its temperature is between its melting point and its boiling point. Suppose that some substance

has a melting point of -36.14 degrees Celsius and a boiling point of 324.84 degrees Celsius . What is the range of temperatures in degrees Fahrenheit for which this substance is not in a liquid​ state?
Mathematics
1 answer:
a_sh-v [17]3 years ago
3 0

Answer:

i. When the temperature is above 616.712^{o}F, it changes to gas.

ii. When the temperature is below -33.052^{o}F, it changes to solid.

Step-by-step explanation:

Matter generally exists in either a solid, liquid or gaseous form. With each phase having a certain range of temperature.

Temperature scale of a given substance can be either in Celsius, Fahrenheit or Kelvin. And conversion from one scale to another can be achieved. Example, Celsius scale can be converted to Fahrenheit by:

F = \frac{9}{5} θ + 32

where: F is the equivalent temperature in Fahrenheit, θ is the value of temperature in degree Celsius.

Given that: melting point of the substance = -36.14^{o}C

⇒ F =  \frac{9}{5} x -36.14^{o} + 32

      = -33.052^{o}F

The boiling point = 324.84^{o}C

F =  \frac{9}{5} x  324.84^{o} + 32

  = 616.712^{o}F

The melting point of the substance is -33.052^{o}F, and boiling point is 616.712^{o}F.

Therefore, the range of temperatures for which the substance is not in a liquid state are:

i. When the temperature is above 616.712^{o}F, it changes to gas.

ii. When the temperature is below -33.052^{o}F, it changes to solid.

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Poisoning by the pesticide DDT causes convulsions in humans and other mammals. Researchers seek to understand how the convulsion
denpristay [2]

Answer:

Step-by-step explanation:

Hello!

The researchers made a comparative experiment to test the convulsive effects of DDT. They had two groups of 6 rats each, one of them was given the pesticide, the other wasn't treated with any kind of substance (control group) Then the nerve activity was measured.

Given the samples:

X₁: Electrical response of a rat's leg after the rat has eaten poison. (height of the second spike)

12.207, 16.869, 25.050, 22.429, 8.456, 20.589

n₁= 6

X[bar]₁= 17.60

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X₂: Electrical response of a rat's leg. (height of the second spike)

11.074, 9.686, 12.064, 9.351, 8.182, 6.642

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X[bar]₂= 9.50

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The objective is to compare both samples electrical response to determine if the relative height of the second spike is affected by DDT (if it is the mean height of the spike of rats that are poisoned will be different to the mean height of the spike of the rats that aren't poisoned)

H₀: μ₁ = μ₂

H₁:  μ₁ ≠ μ₂

α: 0.05 (the significance level is not determined so I've choosen the most common one.)

I've performed a normality test for both samples, with p-value 0.7078 X₁ has a normal distribution and p-value 0.9367 X₂ has a normal distribution.

To compare both means, considering that both samples are small, and there is no information regarding the population variances, the most accurate statistic to use is the student t.

The p-value for variance homogenecy test is 0.1108 so the population variances are unknown but equal, so the test is a pooled t with pooled sample variance:

(Note I've compared all p-values to α: 0.05 )

t= \frac{(X[bar]_1-X[bar]_2)-(Mu_1-Mu_2)}{Sa\sqrt{\frac{1}{n_1}+\frac{1}{n_2}  } }

Sa^2= \frac{(n_1-1)S^2_1+(n_2-1)S^2_2}{n_1+n_2-2}

Sa^2= \frac{(5*40.20)+(5*3.80)}{6+6-2} = 22

Sa= 4.69

t_{H_0}= \frac{17.60-9.50-0}{4.69\sqrt{\frac{1}{6}+\frac{1}{6}  } }= 2.99

This test is two tailed with n₁+n₂-2 degrees of freedom, the p-value is:

p- value: 0.013574

The decision at 5% significance level is to reject the null hypothesis.

b. The p-value in a. indicates that 1.3574% of all samples taken will result that the mean height of the spike of rats poisoned with DDT will be different from the mean height of the spike of rats that were not poisoned.

I hope it helps!

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Step-by-step explanation:

I graphed the function on the graph below so you can see that it rises to the right and goes through the point (0,-2).

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