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Step2247 [10]
3 years ago
6

A swimming pool's large drain will empty the pool in 3 hours while its smaller drain takes 6 hours. If both drains are opened, h

ow long will it take to empty the pool?
Mathematics
2 answers:
makkiz [27]3 years ago
8 0

Answer:

2 hours

Step-by-step explanation:

6 divided by 3 is 2

Im pretty sure this is correct :)

Alisiya [41]3 years ago
8 0

Answer:

1.5 hours

Step-by Step Explanation:

the smaller drain takes 2x as long by itself then the bigger drain, so it will be 2x as quicker if both are opened.

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FinnZ [79.3K]

Answer:

7997.06 is the awnser to the question

8 0
2 years ago
Read 2 more answers
Find the area of a regular triangle with side length of 15.5 inches
Ganezh [65]

Answer:

Brainliest pls

Step-by-step explanation:

A≈104.03in²

5 0
2 years ago
Jeremiah plans on building a 5 meter long garden walkway that is paved with square stones that measure " $ meter on each side. T
larisa86 [58]

Complete question :

Jeremiah plans on building a 5 meter long garden walkway that is paved with square stones that measure " 5/6 meter on each side. There will be no spaces between the stones. How many stones will be needed to complete the garden walkway?

Answer:

12

Step-by-step explanation:

Given that:

Length of square block to be used = 5/6 meters

Length of garden. Walkway = 5 m

Since length of walkway is the same on both sides, then the Total length = 5m + 5m = 10 meters

Number of square stones required :

Total length of walkway / side length of stones to be used

= 10 meters ÷ (5/6) meters

= 10 * 6/5

= 60 / 5

= 12 stones

8 0
2 years ago
Find the limit. Use l'Hospital's Rule if appropriate. If there is a more elementary method, consider using it.
grandymaker [24]
(2x+1)^{\cot x}=\exp\left(\ln(2x+1)^{\cot x}\right)=\exp\left(\cot x\ln(2x+1)\right)=\exp\left(\dfrac{\ln(2x+1)}{\tan x}\right)

where \exp(x)\equiv e^x.

By continuity of e^x, you have

\displaystyle\lim_{x\to0^+}\exp\left(\dfrac{\ln(2x+1)}{\tan x}\right)=\exp\left(\lim_{x\to0^+}\dfrac{\ln(2x+1)}{\tan x}\right)

As x\to0^+ in the numerator, you approach \ln1=0; in the denominator, you approach \tan0=0. So you have an indeterminate form \dfrac00. Provided the limit indeed exists, L'Hopital's rule can be used.

\displaystyle\exp\left(\lim_{x\to0^+}\dfrac{\ln(2x+1)}{\tan x}\right)=\exp\left(\lim_{x\to0^+}\dfrac{\frac2{2x+1}}{\sec^2x}\right)

Now the numerator approaches \dfrac21=2, while the denominator approaches \sec^20=1, suggesting the limit above is 2. This means

\displaystyle\lim_{x\to0^+}(2x+1)^{\cot x}=\exp(2)=e^2
7 0
3 years ago
What is the value of X?
Troyanec [42]

All three sides of the triangle are the same so youcan set two of the equations equal to each other and solve for x:


4x-10 = 3x +2

Add 10 to each side:

4x = 3x + 12

Subtract 3x from each side:

x = 12

3 0
3 years ago
Read 2 more answers
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