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expeople1 [14]
3 years ago
13

What is the slope of a line perpendicular to 24x-9y=63

Mathematics
1 answer:
Gelneren [198K]3 years ago
3 0
In order to find the slop it is probably best to put the equation in y=mx+b form. This means to get y by itself on one side. 
24x-9y=63 will then become -9y=63-24x in which y has been isolated.
Then you should divided by -9 to get the final form: y=24x/9 -63/9.
 Now you can get the slope of the perpendicular line by taking the slope of the original equation and finding its reciprocal which is -9/24x. This is your answer. 
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Ralph complete 1/2 of his homework before dinner and 2/8 of his homework after dinner.How much more homework does Ralph have to
xxTIMURxx [149]

Answer:

7/8

Step-by-step explanation:

7/8 because he completed 4/8 (half) before he finished dinner. 4+2=6. So/ it should be 7/8.

5 0
3 years ago
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In the rectangle below, EI = 2x+6, FI= 5x-6, and m ZIFE = 490.
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3 0
3 years ago
The frequency distribution of weights (in kg) of 40 persons is given below.
gregori [183]

Answer: (a) 4

(b) 5

(c) 14

(d)

Class interval       Class mark

30 - 35                       \dfrac{35+30}{2}=32.5

35 - 40                       \dfrac{35+40}{2}=37.5

40 - 45                        \dfrac{40+45}{2}=42.5

45 - 50                        \dfrac{45+50}{2}=47.5

50 - 55                        \dfrac{50+55}{2}=52.5

Step-by-step explanation:

The data of 40 persons is given as :

Weights (in kg)    Frequency

30 - 35                  6

35 - 40                   13

40 - 45                   14

45 - 50                   4

50 - 55                  3

(a)

<em>Lower limit is the lowest number in a class interval .</em>

So, is the lower limit of fourth-class interval (45 - 50) is 4.

(b)

<em>Class size = Upper limit - lower limit </em>

So, Class size of first class interval = 35-30=5

Thus , class size of each interval is 5. [ class size remains same]

(c)

Highest frequency in table = 14 which is corresponding to 40 - 45   .

Thus , 40 - 45  is the class interval has the highest frequency.

(d)

<em>Class mark is the mid value of each class interval.</em>

<em>Class interval = </em>\dfrac{(\text{Upper limit+Lower limit})}{2}

Class interval       Class mark

30 - 35                       \dfrac{35+30}{2}=32.5

35 - 40                       \dfrac{35+40}{2}=37.5

40 - 45                        \dfrac{40+45}{2}=42.5

45 - 50                        \dfrac{45+50}{2}=47.5

50 - 55                        \dfrac{50+55}{2}=52.5

8 0
3 years ago
The radius of a circular sign is 12 inches. Equal parts of the sign are painted red and yellow. How many square inches are paint
AnnZ [28]

Answer:

226.08 square inches

Step-by-step explanation:

Area of a circle is given by

A=\pi r^{2}

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A=0.5\pi r^{2}

Substituting 12 inches for r then

A=0.5\pi 12^{2}=226.08 in^{2}

Therefore, each paint occupies approximately 226.08 square inches

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The answer is 0 :D :)


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