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Ronch [10]
2 years ago
11

How many solutions does this system have? 6x+3y = 9 2x + y = 3

Mathematics
1 answer:
Lerok [7]2 years ago
4 0

Answer:

The system of equation has infinite solution.

Step-by-step explanation

2x + y = 3

6x = 9 – 3y

First we re-write the second equation in standard form

So, we add 3y both sides

6x+3y=9 ---------------- (2)

2x+y = 3-----------------  (1)

3(2x)+3y = 3(3)

6x+3y=9

6x-6x + 3y-3y = 9-9

0=0

LHS=RHS

This is true statement. If statement is true then infinite number of many solution.

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Answer:

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Step-by-step explanation:

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3 0
2 years ago
A ball is dropped from a height of 10 meters. Each time it bounces, it reaches 50 percent of its previous height. The total vert
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After every drop,the ball bounces to half it's previous height. With that understood.

1st drop -The ball drops 10m

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2nd drop - 5m down

2nd bounce - 2.5m up
3rd drop - 2.5m down

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4th drop - 1.25m down

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5th/last drop - 0.625m down

To find the total vertical distance, you add them all.

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6 0
3 years ago
Find the value of x that makes m|n.<br> m<br> (6x + 10)<br> (2x + 26)<br> The value of x is ?
olga nikolaevna [1]

Answer:

x is 9

Step-by-step explanation:

6x+10=2x+26

-2x          -2x

4x+10=26

   +10  +10

4x=36

---   ---

4    4

x=9

8 0
3 years ago
Qwertyuiopasdfghjklzxcvbnm
Marina CMI [18]

Answer:

Ok for your question 1+1. In my calculations, that is 2.

I hoped this helped have a good day :)

8 0
3 years ago
Read 2 more answers
The radius of the base of a cylinder is increasing at a rate of 7 millimeters per hour. The height of the cylinder is fixed at 1
Ilya [14]

Answer:

The rate of change of the volume of the cylinder at that instant = 791.28\ mm^3/hr

Step-by-step explanation:

Given:

Rate of increase of base of radius of base of cylinder = 7 mm/hr

Height of cylinder = 1.5 mm

Radius at a certain instant = 12 mm

To find rate of change of volume of cylinder at that instant.

Solution:

Let r represent radius of base of cylinder at any instant.

Rate of increase of base of radius of base of cylinder can be given as:

\frac{dr}{dt}=7\ mm/hr

Volume of cylinder is given by:

V=\pi\ r^2h

Finding derivative of the Volume with respect to time.

\frac{dV}{dt}=\pi\ h\ 2r\frac{dr}{dt}

Plugging in the values given:

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\frac{dV}{dt}=252\pi

Using \pi=3.14

\frac{dV}{dt}=252(3.14)

\frac{dV}{dt}=791.28\ mm^3/hr (Answer)

Thus rate of change of the volume of the cylinder at that instant = 791.28\ mm^3/hr

6 0
2 years ago
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