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Lapatulllka [165]
3 years ago
9

ASAPPP 80 POINTSS How many times as large as the radius of a hydrogen atom are the radii of the mercury and the radii of the ura

nium atoms?
Show your work
Mathematics
2 answers:
Maru [420]3 years ago
4 0

Answer:how many times as large is the approximite radius of a mercury atom, 1.50*10^-10 meter, as the approximite radius of a hydrogen atom, 2.5*10^-11 meter?

Step-by-step explanation:

Fittoniya [83]3 years ago
3 0

Answer:

divide 1.5x10^-10 by 2.5x10^-11 which is 6 meaning the Mercury atom is 6 times larger than a hydrogen atom.

Step-by-step explanation:

im sure thats right !

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3) What is the mean value of the data?
soldi70 [24.7K]
The mean - add all the numbers (data) divided by the amount. 4+3+1+1+2+4+1 =16 16/7 = 2.28
The median - the middle number.
The mode - the most common number.
8 0
3 years ago
20 points
SVEN [57.7K]

Answer:

60in

Step-by-step explanation:

Given data

Length= 24 in

Width = 18 in

Diagonally, we need to find using the Pythagoras theorem

D^2= L^2+W^2

D^2= 24^2+18^2

D^2= 576+324

D^2= 900

Square both sides

D= √900

D= 30 in

For both sides

=30*2= 60in

8 0
3 years ago
HELP!!! ASAP!!!
ololo11 [35]

1+1+2+2+3+3+4+4+5+5 is your answer. If it's wrong I'm sorry

7 0
2 years ago
PlzplPzlpzlzpzl .......i beg u do this easy question for me ....​
jeka94

Answer:  -p^2-(q+r)^2

Work Shown:

I'm assuming your teacher wants you to factor as much as possible.

-p^2-q^2-r^2-2qr\\\\-p^2-q^2-2qr-r^2\\\\-p^2-(q^2+2qr+r^2)\\\\-p^2-(q+r)^2\\\\

In the last step, I used the rule that (a+b)^2 = a^2+2ab+b^2

We cannot factor any further. If the first term was p^2 instead of -p^2, then we could use the difference of squares factoring rule.

5 0
2 years ago
Solve for v in terms of s, t, v. u=-tsv
mrs_skeptik [129]

Suppose an object starts moving at u and gains an acceleration of a. After time t, it gets a speed v after travelling a distance of s.

a = (v - u) / t => v - u = at

v = u + at

s = ut + 1/2(v - u) t

s = ut + 1/2 (at) t

s = ut + 1/2 at2

s = ut + 1/2 at2

v2 = (u + at)2

v2 =u2 + 2uat + a2t2

v2 = u2 + 2a (ut + 1/2 at2)

v2 = u2 + 2as

v2 = u2 + 2as

6 0
3 years ago
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