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2 years ago

Simplify |-10| + |5|

Mathematics

2 answers:

nekit [7.7K]2 years ago

6 0

Answer:

Answer: 15

Step-by-step explanation:

zlopas [31]2 years ago

5 0

Answer: 15

Step-by-step explanation:

Simplify |-10| to 10.

10+∣5∣

Simplify.

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Ken jumps 1 1/5 metres steve jumps 1.5 metres steve jumps further than ken how much further does steve jump than Ken?

monitta

Answer:0.3 m

Step-by-step explanation:

Given

Ken can Jump $1\ \frac{1}{5}\ m$

Steve can Jump $1.5\ m$

Converting mixed fraction into a fraction

$\Rightarrow 1\ \dfrac{1}{5}=\dfrac{1\times 5+1}{5}\\\\\Rightarrow \dfrac{6}{5}\ m=1.2\ m$

The difference between their Jumps is

$\Rightarrow 1.5-1.2=0.3\ m$

Steve Jumps 0.3 m more than ken

5 0

2 years ago

Find x A. 4√6 B. 4√6/3 C. 16√6/3 D. 32√3/3

Cerrena [4.2K]

Answer:

Step-by-step explanation:

let hypotenuse of triangle with 60°=y

$\frac{8\sqrt{2}}{y} =sin ~60\\8 \sqrt{2}=y \times \frac{\sqrt{3}}{2} \\y=\frac{16 \sqrt{2}}{\sqrt{3}} =\frac{16 \sqrt{6}}{3}$

4 0

2 years ago

I need help with C, thank you.

guapka [62]

Simple....

$\frac{3}{4} x\ \textless \ \frac{9}{2}$

x<6

This means that on your graph at 6 it's a circle (not colored in) and it goes to the left indefinitely...

Thus, your answer.

6 0

2 years ago

Solve the equation. Round your answer to the nearest hundredth. 47 +3.81k = -41

Harman [31]

Answer:

i have no idea but if i had to guess it would be around -3.00k or -4.00k

Step-by-step explanation:

4 0

3 years ago

Consider rolling two fair dice and observing the number of spots on the resulting upward face of each one. Letting A be the even

Allushta [10]

Answer:

$P(E|A)= \frac{10}{11}$

Step-by-step explanation:

Given

Two rolls of die

$E \to$ one of the outcomes is 6

$A \to$ atleast one is 6

Required

P(E|A)

First, list out the outcome of each

$E = \{(1,6),(2,6),(3,6),(4,6),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5)\}$

$A = \{(1,6),(2,6),(3,6),(4,6),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)\}$

So:

$P(E|A)= \frac{n(E\ n\ A)}{n(A)}$

Where:

$E\ n\ A = \{(1,6),(2,6),(3,6),(4,6),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5)\}$

$n(E\ n\ A) = 10$

$n(A) = 11$

So:

$P(E|A)= \frac{10}{11}$

7 0

2 years ago