The answer is 3.63. seconds.
Second order reaction is the reaction in which the rate of reaction depends on either the concentration of two reactant species or on the two times the concentration of single reactant species.
What is the integrated rate law for the second-order reaction?
- The integrated rate law that relates the concentration, time and rate constant for the second-order reaction is:
![\frac{1}{[A]} =\frac{1}{[A]_{0} } +kt](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B%5BA%5D%7D%20%3D%5Cfrac%7B1%7D%7B%5BA%5D_%7B0%7D%20%7D%20%2Bkt)
Where
![\[\begin{array}{l}{\rm{[A] - concentration\ of\ reactant\ A\ at\ time\ t}}\\{{\rm{[A]}}_0}{\rm{ - initial\ concentration\ of\ reactant\ A}}\\{\rm{t - time}}\\{\rm{k - rate\ constant}}\end{array}\]](https://tex.z-dn.net/?f=%5C%5B%5Cbegin%7Barray%7D%7Bl%7D%7B%5Crm%7B%5BA%5D%20%20-%20%20concentration%5C%20of%5C%20reactant%5C%20A%5C%20at%5C%20time%5C%20t%7D%7D%5C%5C%7B%7B%5Crm%7B%5BA%5D%7D%7D_0%7D%7B%5Crm%7B%20-%20%20initial%5C%20concentration%5C%20of%5C%20reactant%5C%20A%7D%7D%5C%5C%7B%5Crm%7Bt%20-%20time%7D%7D%5C%5C%7B%5Crm%7Bk%20%20-%20%20rate%5C%20constant%7D%7D%5Cend%7Barray%7D%5C%5D)
- Now, in the given question,
k = 
![[NO_{2} ]= 0.62\ M](https://tex.z-dn.net/?f=%5BNO_%7B2%7D%20%5D%3D%200.62%5C%20M)
![[NO_{2} ]_{0} = 0.28\ M](https://tex.z-dn.net/?f=%5BNO_%7B2%7D%20%5D_%7B0%7D%20%3D%200.28%5C%20M)
- Thus, using the rate law, the time is calculated as-
Therefore,
- Hence, the it would take 3.63 seconds for the concentration of
to decrease from 0.62 M to 0.28 M if the reaction is second order.
To learn more about second order reaction visit:
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A bond allows metal to conduct electricity <span />
Answer: Sediment Transport by Wind
Explanation: Like flowing water, wind picks up and transports particles. Wind carries particles of different sizes in the same ways that water carries them (Figure below). Tiny particles, such as clay and silt, move by suspension. They hang in the air, sometimes for days.
There are 10 hydrogen atoms that bind and there are 2 pairs of free electrons in the non-binding O atom
<h3>Further explanation</h3>
Aldehydes are alkane-derived compounds containing carbonyl groups (-CO-) where one bond binds to an alkyl group while another binds to a hydrogen atom.
The general structure is R-CHO with the molecular formula :
Naming is generally the same as the alkane by replacing the suffix with -al
Butanal or butyraldehyde is an aldehyde which has 4 C atoms
Inside the structure there are 3 atoms involved in bonding:
- 1. Atom C with 4 valence electrons, requires 4 electrons to reach the octet
- 2. Atom O with 6 valence electrons, requires 2 electrons to reach the octet
- 3. Atom H with 1 valence electron, requires 1 electron to reach a duplet
In describing Lewis's structure the steps that can be taken are:
- 1. Count the number of valence electrons from atoms in a molecule
- 2. Give each bond a pair of electrons
- 3. The remaining electrons are given to the atomic terminal so that an octet is reached
- 4. The remaining electrons that still exist in the central atom
- 5. If the central atom is not yet octet, free electrons are drawn to the central atom to form double bonds
In the Butanal structure (C₄H₈O) there is 1 double bond of the functional group (-CHO) between the C atom and the O atom
<h3>Learn more:
</h3>
Adding electron dots
brainly.com/question/6085185
Ionic bonding
brainly.com/question/1603987
Formal charge
brainly.com/question/7190235
Keywords: butanal, aldehyde, Lewis structure, a valence electron
Question: Baking a Cake Without Flour.
Hypothesis: I think that when I remove the flour from the standard cake recipe, I'll end up with a flat but tasty cake.
Procedure: I baked two cakes during my experiment. For my control, I baked a cake following a normal recipe. I used the Double Fudge Cake recipe on page 292 of the Betty Crocker Cookbook. For my experimental cake, I followed the same recipe but left out the flour. I first obtained a 2-quart mixing bowl.
Results: My control cake, which I cooked for 25 minutes, measured 4 cm high. Eight out of ten tasters that I picked at random from the class found it to be an acceptable dessert. After 25 minutes of baking, my experimental cake was 1.5 cm high and all ten tasters refused to eat it because it was burnt to a crisp.
What did I learn?/Conclusion: Since the experimental cake burned, my results did not support my hypothesis. I think that the cake burned because it had less mass, but cooked for the same amount of time. I propose that the baking time be shortened in subsequent trials.
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I hope this helped :))
