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Kryger [21]
3 years ago
11

How many protons are there in 2.5 l of liquid water?

Chemistry
1 answer:
ziro4ka [17]3 years ago
4 0
The density of liquid water is 1 kg/L. 

Mass of water = (1 kg/L)(2.5 L)(1000 g/1 kg) = 2500 g water

The molar mass of water is 18 g/mol.

Moles of water = 2500 g / 18 g/mol = 138.889 mol water

According to Avogadro's number, in one mole of any substance, there are 6.022×10²³ atoms.

Atoms of water = 138.889 mol * 6.022×10²³ atoms/mol = 8.364×10²⁵ atoms of water

In every atom of water, there are 10 protons: 8 from one oxygen atom, and 1 each from the two hydrogen atoms.

Protons of water = 8.364×10²⁵ atoms * 10 protons/atom
<em>Protons of water = 8.364×10²⁶ </em>
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Heat is being transferred from the ground to the air above it by conduction. Explain how this is possible.
Klio2033 [76]

Answer:

Conduction directly affects air temperature only a few centimeters into the atmosphere. During the day, sunlight heats the ground, which in turn heats the air directly above it via conduction. At night, the ground cools and the heat flows from the warmer air directly above to the cooler ground via conduction.

Explanation:

4 0
3 years ago
Read 2 more answers
When 136g of glycine are dissolved in of a certain mystery liquid , the freezing point of the solution is lower than the freezin
loris [4]

The given question is incomplete. The complete question is:

When 136 g of glycine are dissolved in 950 g of a certain mystery liquid X, the freezing point of the solution is 8.2C lower than the freezing point of pure X. On the other hand, when 136 g of sodium chloride are dissolved in the same mass of X, the freezing point of the solution is 20.0C lower than the freezing point of pure X. Calculate the van't Hoff factor for sodium chloride in X.

Answer: The vant hoff factor for sodium chloride in X is 1.9

Explanation:

Depression in freezing point is given by:

\Delta T_f=i\times K_f\times m

\Delta T_f=T_f^0-T_f=8.2^0C = Depression in freezing point

K_f = freezing point constant

i = vant hoff factor = 1 ( for non electrolyte)

m= molality =\frac{136g\times 1000}{950g\times 75.07g/mol}=1.9

8.2^0C=1\times K_f\times 1.9

K_f=4.32^0C/m

Now Depression in freezing point for sodium chloride is given by:

\Delta T_f=i\times K_f\times m

\Delta T_f=20.0^0C = Depression in freezing point

K_f = freezing point constant  

m= molality = \frac{136g\times 1000}{950g\times 58.5g/mol}=2.45

20.0^0C=i\times 4.32^0C\times 2.45

i=1.9

Thus vant hoff factor for sodium chloride in X is 1.9

3 0
3 years ago
A sample of an ideal gas at 1.00 atm and a volume of 1.72 l was placed in a weighted balloon and dropped into the ocean. as the
kolbaska11 [484]
If we analyze the situation analytically, there are situations or states. Then, we are also given with 2 values of pressure and 1 value of volume. Lastly, temperature was set as constant. Thus, this means we use the Boyle's Law.

P₁V₁ = P₂V₂
Let's find V₂.
(1 atm)(1.72 L) = (35 atm)(V₂)
Solving for V₂,
<em>V₂ = 0.049 L</em>
7 0
3 years ago
Why is U-235 the most common nuclear fuel instead of the more abundant U-238? State a clear topic sentence and support it with e
GREYUIT [131]
<h3><u>Answer and explanation</u>;</h3>
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  • In a nuclear power station fissioning of uranium atoms replaces the burning of coal or gas.  Heat created by splitting the U-235 atoms is then used to make steam which spins a turbine to drive a generator, producing electricity.
3 0
3 years ago
1. Describe the difference between an electron and a proton in terms of their charge.​
Zarrin [17]

Explanation:

Protons have a positive charge. Electrons have a negative charge. The charge on the proton and electron are exactly the same size but opposite. Neutrons have no charge.

5 0
2 years ago
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