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wolverine [178]

3 years ago

5

Please help!!!!

1 answer:

stealth61 [152]3 years ago

3 0

Answer:

Cells are extremely small.

Explanation:

As Mendel describes in this story, cells are so small they cannot normally be seen with the naked eye. ... The total organism remains the same throughout this process, and (usually) has a longer time on earth than any one of its cells.

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Round to two significant figures 233.354

Rom4ik [11]

Answer:

230 because it is only two numbers higher than 0

4 0

3 years ago

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HELPPP!! Which of the following describes light? (Select all that apply.)

Mnenie [13.5K]

Answer: A.Light travels in a straight line., B.Light behaves in a predictable way. , D.Light curves around corners or obstructions

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2 years ago

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When the nuclide uranium-234 undergoes alpha decay: the name of the product nuclide is . the symbol for the product nuclide is?

Schach [20]

Answer is: <span>name of the product nuclide is thorium-230.
</span>

<span>Alpha particle is nucleus of a helium-4 atom, which is made of two protons and two neutrons.
²³</span>⁴U → ²³⁰Th + α (alpha particle).

Alpha decay is radioactive decay in which an atomic nucleus emits an alpha particle (helium nucleus) and transforms into an atom with an atomic number that is reduced by two and mass number that is reduced by four.

5 0

3 years ago

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How many liters of hydrogen gas will be produced at STP from the reaction of 7.179×10^23 atoms of magnesium with 54.219g of phos

Alexeev081 [22]

Answer: The volume of hydrogen gas produced will be, 12.4 L

Explanation : Given,

Mass of $H_3PO_4$ = 54.219 g

Number of atoms of $Mg$ = $7.179\times 10^{23}$

Molar mass of $H_3PO_4$ = 98 g/mol

First we have to calculate the moles of $H_3PO_4$ and $Mg$ .

$\text{Moles of }H_3PO_4=\frac{\text{Given mass }H_3PO_4}{\text{Molar mass }H_3PO_4}$

$\text{Moles of }H_3PO_4=\frac{54.219g}{98g/mol}=0.553mol$

and,

$\text{Moles of }Mg=\frac{7.179\times 10^{23}}{6.022\times 10^{23}}=1.19mol$

Now we have to calculate the limiting and excess reagent.

The balanced chemical equation is:

$3Mg+2H_3PO_4\rightarrow Mg(PO_4)_2+3H_2$

From the balanced reaction we conclude that

As, 3 mole of $Mg$ react with 2 mole of $H_3PO_4$

So, 0.553 moles of $Mg$ react with $\frac{2}{3}\times 0.553=0.369$ moles of $H_3PO_4$

From this we conclude that, $H_3PO_4$ is an excess reagent because the given moles are greater than the required moles and $Mg$ is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of $H_2$

From the reaction, we conclude that

As, 3 mole of $Mg$ react to give 3 mole of $H_2$

So, 0.553 mole of $Mg$ react to give 0.553 mole of $H_2$

Now we have to calculate the volume of $H_2$ gas at STP.

As we know that, 1 mole of substance occupies 22.4 L volume of gas.

As, 1 mole of hydrogen gas occupies 22.4 L volume of hydrogen gas

So, 0.553 mole of hydrogen gas occupies $0.553\times 22.4=12.4L$ volume of hydrogen gas

Therefore, the volume of hydrogen gas produced will be, 12.4 L

4 0

3 years ago

Problem Page Question A major component of gasoline is octane C8H18. When liquid octane is burned in air it reacts with oxygen O

KATRIN_1 [288]

Answer:

0.3mol C8H18

Explanation:

For this we must first look at the reaction taking place:

C8H18+O2 --> H2O + CO2

Balancing the equation we get:

2(C8H18)+25(O2) --> 18(H2O) + 16(CO2)

Form there we now need to know how many moles of Octane are needed to produce 2.4moles of H2O. The conversion is as follows:

2.4molH2O ((2mol of C8H18)/(18mol of H2O)) = 0.3mol C8H18

3 0

3 years ago