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Elina [12.6K]
3 years ago
15

Find the product of all positive divisors of 288.

Mathematics
2 answers:
lilavasa [31]3 years ago
8 0

Answer:

Step-by-step explanation:

2 * 3 * 4 * 6 * 8 * 9 * 12 * 16* 18 * 24 * 32 * 36 * 48 * 96 * 144

Some teachers would include 288. I would not.

You can get the actual answer by using the calculator that came with your computer. An ordinary calculator will not work because the answer will come out in scientific notation.

657,366,253,849,018,368 is the answer.

irinina [24]3 years ago
6 0

Answer:

<em>The</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em>1</em><em>.</em><em>5</em><em>1</em><em>4</em><em>5</em><em>7</em><em>1</em><em>8</em><em>9</em><em>4</em><em>×</em><em>1</em><em>0</em><em>^</em><em>2</em><em>1</em><em>.</em>

Step-by-step explanation:

<em>Here</em><em>, </em><em> </em><em>the</em><em> </em><em>divisors</em><em> </em><em>of</em><em> </em><em>2</em><em>8</em><em>8</em><em> </em><em>are</em><em>,</em>

<em>1</em><em>,</em><em>2</em><em>,</em><em>3</em><em>,</em><em>4</em><em>,</em><em>6</em><em>,</em><em>8</em><em>,</em><em>9</em><em>,</em><em>1</em><em>2</em><em>,</em><em>1</em><em>6</em><em>,</em><em>1</em><em>8</em><em>,</em><em>2</em><em>4</em><em>,</em><em>3</em><em>2</em><em>,</em><em>3</em><em>6</em><em>,</em><em>4</em><em>8</em><em>,</em><em>7</em><em>2</em><em>,</em><em>9</em><em>6</em><em>,</em><em>1</em><em>4</em><em>4</em><em>,</em><em>2</em><em>8</em><em>8</em><em>.</em>

<em>now</em><em>,</em><em> </em><em>their</em><em> </em><em>product</em><em> </em><em>=</em><em>1</em><em>×</em><em>2</em><em>×</em><em>3</em><em>×</em><em>4</em><em>×</em><em>6</em><em>×</em><em>8</em><em>×</em><em>9</em><em>×</em><em>1</em><em>2</em><em>×</em><em>1</em><em>6</em><em>×</em><em>1</em><em>8</em><em>×</em><em>2</em><em>4</em><em>×</em><em>3</em><em>2</em><em>×</em><em>3</em><em>6</em><em>×</em><em>4</em><em>8</em><em>×</em><em>7</em><em>2</em><em>×</em><em>9</em><em>6</em><em>×</em><em>1</em><em>4</em><em>4</em><em>×</em><em>2</em><em>8</em><em>8</em>

<em>=</em><em>1</em><em>.</em><em>5</em><em>1</em><em>4</em><em>5</em><em>7</em><em>1</em><em>8</em><em>9</em><em>4</em><em>×</em><em>1</em><em>0</em><em>^</em><em>2</em><em>1</em><em>.</em>

<em>is</em><em> </em><em>answer</em><em>. </em>

<em><u>Hope</u></em><em><u> </u></em><em><u>it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

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Three security cameras were mounted at the corners of a triangles parking lot. Camera 1 was 110 ft from camera 2, which was 137
Nata [24]

Answer:

<em>Camera 2nd has to cover the maximum angle, i.e. </em>78.70^\circ.

Step-by-step explanation:

Please have a look at the triangular park represented as a triangle \triangle ABC with sides

a = 110 ft

b = 158 ft

c = 137 ft

1st camera is located at point C, 2nd camera at point B and 3rd camera at point A respectively.

We can use law of cosines here, to find out the angles \angle A, \angle B, \angle C

As per Law of cosine:

cos C = \dfrac{a^{2}+b^2-c^2 }{2ab}\\cos B = \dfrac{a^{2}+c^2-b^2 }{2ac}\\cos A = \dfrac{b^{2}+c^2-a^2 }{2bc}

Putting the values of a,b and c to find out angles \angle A, \angle B, \angle C.

cos C = \dfrac{110^{2}+158^2-137^2 }{2\times 110 \times 158}\\\Rightarrow cos C = \dfrac{12100+24964-18769 }{24760}\\\Rightarrow cos C =0.526\\\Rightarrow C = 58.24^\circ

cos B = \dfrac{110^{2}+137^2-158^2 }{2\times 110 \times 137}\\\Rightarrow cos B = \dfrac{12100+18769 -24964}{30140}\\\Rightarrow cos B = \dfrac{5905}{30140}\\\Rightarrow cos B =0.196\\\Rightarrow B = 78.70^\circ

cos A = \dfrac{158^{2}+137^2-110^2 }{2\times 158 \times 137}\\\Rightarrow cos A = \dfrac{24964+18769-12100}{43292}\\\Rightarrow cos A = \dfrac{31633}{43292}\\\Rightarrow cos A = 0.731\\\Rightarrow A = 43.05^\circ

<em>Camera 2nd has to cover the maximum angle</em>, i.e. 78.70^\circ.

6 0
4 years ago
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