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3 years ago

A solid plastic ball is a sphere with radius 8 in. How much plastic does it take to make one ball? Use 3.14 for pi.

Mathematics

1 answer:

Kryger [21]3 years ago

7 0

Answer:

2,143.57

Step-by-step explanation:

The equation for volume of a sphere is 4/3 x pie x r^3. Plug in 8 for r = 512. 512 x 3.14= 1,607.68. 4/3 x 1,607.68 is about 2,143.57

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Evaluate5− t/3 when t=12

Novosadov [1.4K]

Answer:

$1$

Step-by-step explanation:

$5 - \frac{t}{3} = \frac{5}{1} - \frac{12}{3} = 5 - 4 = 1$

$5 - \frac{t}{3} = \frac{5}{1} - \frac{12}{3} = \frac{15 - 12}{3} = \frac{3}{3} = 1$

Hope this helps ;) ❤❤❤

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3 years ago

Read 2 more answers

Picasso's Phone Shop charges $65.54 for its activation fee plus $13.10 for every gigabyte, g, of data you use over your limit. T

konstantin123 [22]

Answer:

$13.10 represents the rate of change

Step-by-step explanation:

13.1 is the only value in the equation with a variable (g). There is an additional $13.10 charge for every gigabyte used over the limit, and this is the rate of change.

For example, if 5 gigabytes were used over the limit, the charge would be 13.1(5) or $65.50

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2 years ago

Write 1/2 as a percent

Yakvenalex [24]

1/2 as a percent is 0.5

8 0

3 years ago

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Use the definition of a Taylor series to find the first three non zero terms of the Taylor series for the given function centere

Ket [755]

Answer:

$e^{4x}=e^4+4e^4(x-1)+8e^4(x-1)^2+...$

$\displaystyle e^{4x}=\sum^{\infty}_{n=0} \dfrac{4^ne^4}{n!}(x-1)^n$

Step-by-step explanation:

<u>Taylor series</u> expansions of f(x) at the point x = a

$\text{f}(x)=\text{f}(a)+\text{f}\:'(a)(x-a)+\dfrac{\text{f}\:''(a)}{2!}(x-a)^2+\dfrac{\text{f}\:'''(a)}{3!}(x-a)^3+...+\dfrac{\text{f}\:^{(r)}(a)}{r!}(x-a)^r+...$

This expansion is valid only if $\text{f}\:^{(n)}(a)$ exists and is finite for all $n \in \mathbb{N}$ , and for values of x for which the infinite series converges.

$\textsf{Let }\text{f}(x)=e^{4x} \textsf{ and }a=1$

$\text{f}(x)=\text{f}(1)+\text{f}\:'(1)(x-1)+\dfrac{\text{f}\:''(1)}{2!}(x-1)^2+...$

$\boxed{\begin{minipage}{5.5 cm}\underline{Differentiating $e^{f(x)}$}\\\\If $y=e^{f(x)}$, then $\dfrac{\text{d}y}{\text{d}x}=f\:'(x)e^{f(x)}$\\\end{minipage}}$