Answer: you can’t really answer this because you have to how many bags of flour and how many boxes of butter that you have and then youll be able to solve
Step-by-step explanation: maybe if you reword it and edit your question then it’ll make more sense
Answer:
Step-by-step explanation:
To calculate the speed of each one we proceed as follows:
speed=distance/time
a] Noah's speed:
distance=2.5 miles
time=3/5 hours
speed=(2 1/2)/(3/5)
=(5/2)/(3/5)
=5/2×5/3
=25/6
=4 1/6 mi/hr
Emily's speed
distance=3 3/4 miles
time=5/6 hour
thus
speed=(3 3/4)/(5/6)
=15/4)/(5/6)
=15/4×6/5
=4 1/2 mi/hr
Anna's speed:
distance=3 1/3 miles
time=3/5
speed=(3 1/3)/(3/5
=(10/3)/(3/5)
=10/3×5/3
=5 5/9 mi/hr
Anna was the fastest
Answer:
Step-by-step explanation:
Given data:
SS={0,1,2,3,4}
Let probability of moving to the right be = P
Then probability of moving to the left is =1-P
The transition probability matrix is:
![\left[\begin{array}{ccccc}1&P&0&0&0\\1-P&1&P&0&0\\0&1-P&1&P&0\\0&0&1-P&1&P\\0&0&0&1-P&1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccccc%7D1%26P%260%260%260%5C%5C1-P%261%26P%260%260%5C%5C0%261-P%261%26P%260%5C%5C0%260%261-P%261%26P%5C%5C0%260%260%261-P%261%5Cend%7Barray%7D%5Cright%5D)
Calculating the limiting probabilities:
π0=π0+Pπ1 eq(1)
π1=(1-P)π0+π1+Pπ2 eq(2)
π2=(1-P)π1+π2+Pπ3 eq(3)
π3=(1-P)π2+π3+Pπ4 eq(4)
π4=(1-P)π3+π4 eq(5)
π0+π1+π2+π3+π4=1
π0-π0-Pπ1=0
→π1 = 0
substituting value of π1 in eq(2)
(1-P)π0+Pπ2=0
from
π2=(1-P)π1+π2+Pπ3
we get
(1-P)π1+Pπ3 = 0
from
π3=(1-P)π2+π3+Pπ4
we get
(1-P)π2+Pπ4 =0
from π4=(1-P)π3+π4
→π3=0
substituting values of π1 and π3 in eq(3)
→π2=0
Now
π0+π1+π2+π3+π4=0
π0+π4=1
π0=0.5
π4=0.5
So limiting probabilities are {0.5,0,0,0,0.5}