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SOVA2 [1]
2 years ago
13

The exchange rate in some prehistoric village was 6 jagged rocks for every 2 smooth pebbles. Also, one shiny rock could be trade

d for 3 smooth pebbles. If Joaquin has 30 jagged rocks, what is the maximum number of shiny rocks he could trade for?
A. 6
B. 4
C. 5
D. 3
Mathematics
1 answer:
Scrat [10]2 years ago
4 0

30 Jagged rocks are the same 3 shiny rocks using the exchange rates provided(i.e. option D)

What is an exchange rate?

Exchange rate means the rate at which one item exchanges hands with another, for instance, in this case, 6 jagged rocks are equivalent to 2 smooth pebbles.

6 jagged rocks=2 smooth pebbles

divide both sides by 2

6/2 jagged rocks=2/2 smooth pebbles

3 jagged rocks=1 smooth pebble

We can rewrite as below:

1 jagged rock=1/3 smooth pebble

30jagged rocks=1/3*30 smooth pebbles

30 jagged rocks=10 smooth pebbles

Now we need to convert 10 smooth pebbles to shiny rock equivalence

3 smooth pebbles=1 shiny rock

1 smooth pebble=1/3 shiny rock

10 smooth pebbles=1/3*10 shiny rocks

10 smooth pebbles=3 shiny rocks( even though it is 3.33, but the final answer should be rounded to a whole number)

Read more about exchange rate in the link below:

brainly.com/question/2202418

#SPJ1

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Lubov Fominskaja [6]

Answer:

DNE

Step-by-step explanation:

The the given table, we have;

As x approaches -14 from the left, at x = -14.001,  p(x) = 1.96

\lim \limits _{x \to -14^{-}} p(x) = 1.96

As x approaches -14 from the right, at x = -13.999, p(x) = 1.97

\lim \limits _{x \to -14^{+}} p(x) = 1.97

The value of p(x) when x = -14 is \lim \limits _{x \to -14} p(x) = Undefined, or is not definable, therefore, p(x) Does Not Exist (DNE) when x = -14, and we have;

\lim \limits _{x \to -14} p(x)  Does Not Exist, DNE.

3 0
3 years ago
If a cone shaped vase can hold 45 cubic centimeter of water and has a radius of 2 centimeters what is the height of the vase use
xz_007 [3.2K]

Answer:

The height of the vase is h=10.75\ cm

Step-by-step explanation:

we know that

The volume of a cone is equal to

V=\frac{1}{3}\pi r^{2} h

we have

V=45\ cm^{3}

r=2\ cm

\pi =3.14

substitute and solve for h

45=\frac{1}{3}(3.14)(2)^{2} h

135=(3.14)(4)h

135=12.56h

h=135/12.56

h=10.75\ cm

3 0
3 years ago
PLS HELP!! WILL GIVE BRAINLIEST!!!
tester [92]

Answer:

mAB = 49

mABC = 253

mBAC= 156

mACB = 311

Step-by-step explanation:

3 0
2 years ago
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lesantik [10]
It would be answer D your welcome
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2 years ago
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viva [34]
Isosceles triangle
9x + 3 = 84
9x = 81
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answer
<span>D. 9</span>
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