Question

Find the equation of the line whose graph passes through (5,3 ) and has slope 1 / 4.

Answer 1

Answer: y = 1/4x + 1.25 ?? OR y = -4x + 23

Step-by-step explanation:

y = mx + c

3 = 1/4 (5) + c

3 = 1.25 + c

-1.25 from both sides  

c = 1.75

y = 1/4x + 1.75

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perpendicular gradient = -4

y = -4x + c

3 = -4(5) + c

3 = -20 + c

+20 to both sides

c = 23

y = -4x + 23