Let n represent the number.
-13×(n -60) = n +(-59)
-13n +780 = n -59
839 = 14n
839/14 = n = 59 13/14
The number is 59 13/14.
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Check
The difference between the number and 60 is
59 13/14 -60 = -1/14
-13 times that value is
-13*(-1/14) = 13/14
Compare that to the number plus -59
59 13/14 -59 = 13/14 . . . . . the same value, as required.
Answer:
total animal 40
number of bears are 40×3/8=15
number of dogs will be 40 - 15 = 35
Step-by-step explanation:
hope it helped u buddy
A=(v-u)/t
We know a=2.5, v=40, u=10, so:
2.5=(40-10)/t
2.5t=40-10
2.5t=30
Divide both sides by 2.5
t=12 It takes 12 seconds for the car to reach 40m/s
To find out how far it went, you do:
d=v+1/2 at^2
d=10+1/2(2.5)(12)^2
d=10+1/2(2.5)(144)
d=10+(1.25)(72)
d=10+90
d=100m
Hope this helps :)
9514 1404 393
Answer:
- |w -30| > 1.6
- (-∞, 28.4) U (31.6, ∞)
Step-by-step explanation:
1. The snack bags will be rejected if their weight differs from 30 grams by more than 1.6 grams:
|w -30| > 1.6
__
2. This inequality resolves to two inequalities.
w -30 > 1.6
w > 31.6 . . . . . add 30
and
-(w -30) > 1.6
w -30 < -1.6 . . . multiply by -1
w < 28.4 . . . . . add 30
The solution in interval notation is the union of the two disjoint intervals:
(-∞, 28.4) U (31.6, ∞)
The trig functions that you need to deal with are
Sine
Cosine
Tangent
Cotangent
Cosecant
Secant
You need to write a single expression using all six trig functions such that the value of the expression equals 3.
To make this as simple as possible, the first thing I would do is look up the values of these functions and identify which ones are equal to either 1/2 or 1.0 or 2.0
sin(30º) = 1/2
sin(90º) = 1
cos(0º) = 1
cos(60º) = 1/2
tan(45º) = 1
csc(30º) = 2
csc(90º) = 1
sec(0º) = 1
sec(60º) = 2
cot(45º) = 1
If we only had to use three trig functions (sin, cos, tan), one possibility is
tan(45º) + cos(0º)/sin(30º) = 1 + 1/(1/2) = 1 + 2 = 3
noticed how I chose one each of the required functions and the operations so that the result = 3.
Now it is up to you to figure out how to combine all six trig functions so that they equal zero. There are many possibilities for you to choose from..
