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aalyn [17]
4 years ago
10

Please help me........

Mathematics
1 answer:
noname [10]4 years ago
5 0
You will have to write a system of equations.

Let x represent the number of child tickets.
Let y represent the number of adult tickets.

Your two equations will be:

5.60x + 9.10y = 1045.10

x + y = 136


This is going to be solved using the substitution method.

x + y = 136

x = 136 - y

Substitute x for 136 - y in the other equation.

5.60x + 9.10y = 1045.10

5.60(136 - y) + 9.10y = 1045.10

Distribute the outside terms through the terms inside the parenthesis.

761.60 - 5.60y + 9.10y = 1045.10

Combine like terms.

761.60 + 3.5y = 1045.10

Subtract 761.60 from both sides to get 3.5y by itself.

3.5y = 283.5

To get y by itself, divide both sides by 3.5.

y = 81

81 adult tickets were sold that day.
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7.2 Given a test that is normally distributed with a mean of 100 and a standard deviation of 10, find: (a) the probability that
kompoz [17]

Answer:

a)

<em>The probability that a single score drawn at random will be greater than 110  </em>

<em>P( X > 110) = 0.1587</em>

<em>b) </em>

<em>The probability that a sample of 25 scores will have a mean greater than 105</em>

<em>  P( x> 105) = 0.0062</em>

<em>c) </em>

<em>The probability that a sample of 64 scores will have a mean greater than 105</em>

<em> P( x⁻> 105)  = 0.002</em>

<em></em>

<em>d) </em>

<em> The probability that the mean of a sample of 16 scores will be either less than 95 or greater than 105</em>

<em>    P( 95 ≤ X≤ 105) = 0.9544</em>

<em></em>

Step-by-step explanation:

<u><em>a)</em></u>

Given mean of the Normal distribution 'μ'  = 100

Given standard deviation of the Normal distribution 'σ' = 10

a)

Let 'X' be the random variable of the Normal distribution

let 'X' = 110

Z = \frac{x-mean}{S.D} = \frac{110-100}{10} =1

<em>The probability that a single score drawn at random will be greater than 110</em>

<em>P( X > 110) = P( Z >1)</em>

                = 1 - P( Z < 1)

               =  1 - ( 0.5 +A(1))

               = 0.5 - A(1)

               = 0.5 -0.3413

              = 0.1587

b)

let 'X' = 105

Z = \frac{x-mean}{\frac{S.D}{\sqrt{n} } } = \frac{105-100}{\frac{10}{\sqrt{25} } } = 2.5

<em>The probability that a single score drawn at random will be greater than 110</em>

<em>  P( x> 105) = P( z > 2.5)</em>

<em>                    = 1 - P( Z< 2.5)</em>

<em>                    = 1 - ( 0.5 + A( 2.5))</em>

<em>                   = 0.5 - A ( 2.5)</em>

<em>                  = 0.5 - 0.4938</em>

<em>                  = 0.0062</em>

<em>The probability that a single score drawn at random will be greater than 105</em>

<em>  P( x> 105) = 0.0062</em>

<em>c) </em>

let 'X' = 105

Z = \frac{x-mean}{\frac{S.D}{\sqrt{n} } } = \frac{105-100}{\frac{10}{\sqrt{64} } } =  4

<em>The probability that a single score drawn at random will have a mean greater than 105</em>

<em>  P( x> 105) = P( z > 4)</em>

<em>                    = 1 - P( Z< 4)</em>

<em>                    = 1 - ( 0.5 + A( 4))</em>

<em>                   = 0.5 - A ( 4)</em>

<em>                  = 0.5 - 0.498</em>

<em>                  = 0.002</em>

<em> The probability that a sample of 64 scores will have a mean greater than 105</em>

<em> P( x⁻> 105)  = 0.002</em>

<em>d) </em>

<em>Let  x₁ = 95</em>

Z = \frac{x_{1} -mean}{\frac{S.D}{\sqrt{n} } } = \frac{95-100}{\frac{10}{\sqrt{16} } } =  -2

<em>Let  x₂ = 105</em>

Z = \frac{x_{1} -mean}{\frac{S.D}{\sqrt{n} } } = \frac{105-100}{\frac{10}{\sqrt{16} } } =  2

The probability that the mean of a sample of 16 scores will be either less than 95 or greater than 105

P( 95 ≤ X≤ 105) = P( -2≤z≤2)

                         = P(z≤2) - P(z≤-2)

                        = 0.5 + A( 2) - ( 0.5 - A( -2))

                      = A( 2) + A(-2)       (∵A(-2) =A(2)

                     =  A( 2) + A(2)  

                    = 2 × A(2)

                  = 2×0.4772

                  = 0.9544

<em> The probability that the mean of a sample of 16 scores will be either less than 95 or greater than 105</em>

<em>    P( 95 ≤ X≤ 105) = 0.9544</em>

<em>    </em>

7 0
3 years ago
Transformation:rotation,reflection or translation?
sveta [45]

Answer:

Step-by-step explanation:

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7 0
3 years ago
Nina and Krissy have to read different books for Ms. Lester's English class. Nina has read 32 pages of her 110-page book. Krissy
MAVERICK [17]

Answer:

78+55=k

Step-by-step explanation:

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5 0
3 years ago
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Igoryamba
On the first day, they traveled for 10 hours with an average speed of 60 mph.  Which means on the first day they traveled 600 miles.

Since the total distance is 1023 miles and presumably they will be going at a speed of 60 mph.  We divide the miles by the rate:

1023/60  = 17.05

So it will take 17.05 hours to drive the whole way to Florida.

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3 years ago
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and 17 = 10+7

So, 438 \times 17 = (400+30+8) \times (10+7)

438 \times 17 = (400\times 10)+(30 \times 10)+(8 \times 10) +(400 \times 7)+(30 \times 7)+(8 \times 7)

= 438 \times 17 = (4000+300+80+2800+210+56)

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Therefore, the product of 438 and 17 is 7446.

No, Sandra's answer is not correct.

Because she should have expressed 17 as (10+7), then if she multiplied (438 by 10) and (438 by 7). And, then added the results.Then her answer would be correct.

6 0
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