Lets try
centimeter is about 1/2 of a inch
if 28 square cm, the book coould be about 4m by 7cm (aoub the size of a recipt)
if 28 square in the book could be about 4in by 7in (regular size)
I would guess 28 square INCHES (cm is too smal)
First box is EF.
Second box is segment congruence postulate.
Third box is segment additon postulate.
Fourth box is DF. For this one the last sentence basically gives you the answer.
Just so you know for the fourth I guessed on if it's DF lined or DF unlined. I made my educated guess on the fact that the last line doesn't have a line. I hope this helps, and please tell me if I got something wrong, or my explanation wasn't sufficent enough for you.
What you don't want is the value of r(t) becoming negative. Surely that would represent water escaping the reservoir.
How big can (t) get before water actually starts escaping the reservoir?
Essentially, to figure this out r(t) would have to be equal to 0.
700 - 40t = 0
40t=700
t=700/40=17.5
So the first answer is 17.5 seconds. After this amount of time has elapsed the reservoir will start to lose water as r(t) would become negative.
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The reservoir had the least amount of water in it before it was being filled. That was when t=0. The volume of water in the reservoir wasn't negatively impacted as not enough water had escaped it during the 17.5 to 30 second period.
Answer:
x g(x)
1 −10
2 −12
3 −14
Step-by-step explanation:
Substitute the values and do the arithmetic.
Table values for x are 1, 2, 3. We only need to find g(1) to determine which table is the correct choice.
f(1) = 1 +4 = 5 . . . . . . . . . put 1 where x is and do the arithmetic
g(1) = -2·f(1) = -2·5 = -10 . . . . . matches the 3rd choice
