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Sladkaya [172]
3 years ago
5

What is displacement ​

Physics
1 answer:
omeli [17]3 years ago
8 0

The word displacement implies that an object has moved, or has been displaced. Displacement is defined to be the change in position of an object.

Displacement is defined as the act of moving someone or something from one position to another or the measurement of the volume replaced by something else

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Rita places a 2.5 kg block on a frictionless inclined plane that is 30 degrees above horizontal. She applies a horizontal force,
vitfil [10]

Answer:

14.2

Explanation:

find horizontal force of the weight = 2.5kg x 9.8 Sin30 = 12.3 N

to prevent the sliding she needs to pull horizontally

Fh = 12.3 /Cos 30 =14.2N

7 0
3 years ago
SOME HELP PLEASE
ddd [48]

Matter that is composed of a single element and has all the same physical properties would be a substance

Matter that is made of molecules of all the same type are elements

Two atoms chemically bonded together is a compound

A substance made of two or more types of atoms that are not chemically bonded is a mixture

the last one is correct answer

4 0
4 years ago
Read 2 more answers
A rocket traveling at 80 m/s is accelerated uniformly to 152 m/s over a 18 s interval. What is its displacement during this time
IgorLugansk [536]

Recall that with constant acceleration,

x_f-x_i=\dfrac{v_i+v_f}2t

where x_f-x_i is the rocket's displacment, v_i is its initial velocity, v_f its final velocity, and t is time. So

x_f-x_i=\dfrac{80\frac{\mathrm m}{\mathrm s}+152\,\frac{\mathrm m}{\mathrm s}}2(18\,\mathrm s)=2088\,\mathrm m

or just 2100 m if taking significant digits into account.

8 0
3 years ago
An ideal parallel-plate capacitor consists of two parallel plates of area A separated by a distance d. This capacitor is connect
Elina [12.6K]

Answer:

e) half

Explanation:

as we know relation b/w charge(Q) , capacitance (C) and voltage (V) is

Q = CV ...........(i)

we also know capacitance of a capacitor for separation d and area A is

C = ∈₀A/d ...........(ii)

from  the above equation it is clear that C is inversely proportional to separation  if separation doubled  capacitance will reduced to half   and from equation first charge is directly proportional to capacitance.

that s why magnitude of charge will reduced to half  

so option (e) is right answer

3 0
3 years ago
Two electrons are at rest and separated by a distance of 4.32 × 10-10 m. When they are released they accelerate away from each o
sasho [114]

Answer:

Speed of electron when their separation increased by a factor of 4.10 is 9.41 x 10⁵ m/s .

Explanation:

The electric potential energy is given by the relation :

U = \frac{kq_{1}q_{2}  }{r}

Here q₁ and q₂ are the two charge particles and r is the distance between them and k is electric constant.

In this case, there are two electrons which are separated by the distance 4.32 x 10⁻¹⁰ m.

Let e be the electron charge and r₁ be the distance between them. Then, the initial electric potential energy is :

U_{1}  = \frac{ke^{2}   }{r_{1} }

Now, the distance between the electrons increases by the factor of 4.10. Let r₂ be the new distance between them i.e. r₂ = 4.10 r₁.

Thus, the new electric potential energy is :

U_{2}  = \frac{ke^{2}   }{r_{2} }=\frac{ke^{2}   }{4.10r_{1} }

Applying law of conservation of energy :

ΔU  = ΔK

Here ΔU is change in electric potential energy and ΔK is change in kinetic energy.

( U₁  - U₂ ) = ( K₂ - K₁ )

Here K₂ and K₁ are initial and final kinetic energy of electron.

Since, the electron initially is at rest, so its initial kinetic energy is zero. Thus, the above equation becomes:

K₂ = U₁ - U₂

\frac{1}{2}mv^{2}=\frac{ke^{2}   }{r_{1} }- \frac{ke^{2}   }{4.10r_{1} }

Here m and v are the mass and final speed of electron respectively.

v^{2}=\frac{2}{m} \frac{ke^{2}   }{r_{1} }(1- \frac{1  }{4.10 })

Substitute 9.1 x 10⁻³¹ kg for m, 9 x 10⁹ N m² C⁻² for k, 1.6 x 10⁻¹⁹ C for e and 4.32 x 10⁻¹⁰ m for r₁ in the above equation.

v^{2}=\frac{2}{9.1\times10^{-31} } \frac{9\times10^{9}\times(1.6\times10^{-19})^{2}   }{4.32\times10^{-10} }(1- \frac{1  }{4.10 })

v^{2}=8.86\times10^{11}

v = 9.41 x 10⁵ m/s

5 0
3 years ago
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