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bearhunter [10]
3 years ago
14

To understand the distinction between mass and weight and to be able to calculate the weight of an object from its mass and Newt

on's law of gravitation. The concepts of mass and weight are often confused. In fact, in everyday conversations, the word "weight" often replaces "mass," as in "My weight is seventy-five kilograms" or "I need to lose some weight." Of course, mass and weight are related; however, they are also very different. Mass, as you recall, is a measure of an object's inertia (ability to resist acceleration). Newton's 2nd law demonstrates the relationship among an object's mass, its acceleration, and the net force acting on it: F net=ma . Mass is an intrinsic property of an object and is independent of the object's location. Weight, in contrast, is defined as the force due to gravity acting on the object. That force depends on the strength of the gravitational field of the planet: W =mg , where W is the weight of an object, m is the mass of that object, and g⃗is the local acceleration due to gravity (in other words, the strength of the gravitational field at the location of the object). Weight, unlike mass, is not an intrinsic property of the object; it is determined by both the object and its location. Which of the following quantities would be acceptable representations of weight? Check all that apply.
A.) 12.0 lb
B.) 0.34 g
C.) 120 kg
D.) 1600 kN
E.) 0.34 m
F.) 411 cm
Physics
2 answers:
Firdavs [7]3 years ago
6 0

Answer: A.E.

Explanation: To understand the distinction between mass and weight and to be able to calculate the weight of an object from its mass and Newton's law of gravitation. The concepts of mass and weight are often confused. In fact, in everyday conversations, the word "weight" often replaces "mass," as in "My weight is seventy-five kilograms"

Assoli18 [71]3 years ago
4 0

Answer: Option D: 1600 kN

Explanation: The concepts of mass and weight are different, the mass is calculated in grams, and the weight is calculated, like a force, in newtons (or other units of force).

So if we are looking for representations of weight, we are looking for representations of force.

Options A, B and C are written in units of mass (lb, g, kg)

Option D, 1600kN is written in newtons, si it has units of force, this is an acceptable representation of weight.

Options E and F are in units of distance (m, cm)

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3047710272

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7 0
3 years ago
In a double-slit experiment, the slits are illuminated by a monochromatic, coherent light source having a wavelength of 609 nm.
Ray Of Light [21]

Answer:

\Delta x = 3.65 \mu m

Explanation:

As we know that the sixth order maximum will have path difference given as

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here we know that

N = order of maximum

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now we have

N = 6

so we know that

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6 0
2 years ago
Suppose that, while lying on a beach near the equator of a far-off planet watching the sun set over a calm ocean, you start a st
zubka84 [21]

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R=3818Km

Explanation:

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Since you travel 2π radians in 24H, the angle can be calculated as:

\alpha =\frac{2*\pi *t}{24H}  t being expressed in hours.

\alpha =\frac{2*\pi *11.9s*1H/3600s}{24H}=0.000865rad

From the triangle formed by A,B and the center of the planet, we know that:

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6 0
2 years ago
B) If the actual counterweight fitted to this boom was
Lostsunrise [7]

Answer:

50 N

4.2 N

Explanation:

i) The force needed to balance the boom is 2400 N.  If the weight of the counterbalance is 2350 N, then the downward force the park attendant must apply is 50 N.

ii) When the boom is resting on the end support, the normal force is:

∑τ = Iα

-W (0.50) + F (3.0) − N (6.0) = 0

-0.50 W + 3.0 F = 6.0 N

N = (-0.50 W + 3.0 F) / 6.0

N = (-0.50 × 2350 + 3.0 × 400) / 6.0

N ≈ 4.2

6 0
2 years ago
I NEED HELP ASAP DUE TOMMORW
solniwko [45]
The water was heavier since it was more concentrated


8 0
3 years ago
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